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Tcecarenko [31]
3 years ago
6

A submarine 50.2 m below the surface of the ocean

Mathematics
1 answer:
Harman [31]3 years ago
8 0

Answer:

101.5 m

Step-by-step explanation:

What you have to do is 50.2 + 15.6 which equals 65.8, and then you add another 35.7 and the answer would be 101.5 m

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Tim knows the volume and base area of a wooden chest that is in the shape of a rectangular prism. If the volume is 5/24 cubic un
Masteriza [31]
Height is 1 1/24 unit.

Given:
volume = 5/24 unit³
base area = 1/5 unit²

Rectangular prism:
volume = length * width * height
base area = length * width

Volume = base area * height

height = volume / base area
h = 5/24 ÷ 1/5
h = 5/24 * 5/1 = 5*5 /24*1 = 25/24 = <span>1 1/24 unit</span>
5 0
3 years ago
An automobile manufacturer has discovered that 20% of all the transmissions it installed in a particular style of truck are defe
Hatshy [7]

Answer:

0.148 = 14.8% probability that they will need to order at least one more new transmission

Step-by-step explanation:

For each transmission, there are only two possible outcomes. Either it is defective after a year of use, or it is not. The probability of a transmission being defective is independent of any other transmission. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of all the transmissions it installed in a particular style of truck are defective after a year of use.

This means that p = 0.2

Sold seven trucks:

This means that n = 7

It has two of the new transmissions in stock. What is the probability that they will need to order at least one more new transmission?

This is the probability that at least 3 are defective, that is:

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{7,0}.(0.2)^{0}.(0.8)^{7} = 0.2097

P(X = 1) = C_{7,1}.(0.2)^{1}.(0.8)^{6} = 0.3670

P(X = 2) = C_{7,2}.(0.2)^{2}.(0.8)^{5} = 0.2753

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2097 + 0.3670 + 0.2753 = 0.852

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.852 = 0.148

0.148 = 14.8% probability that they will need to order at least one more new transmission

6 0
3 years ago
What is the value of the expression below when x equals 5?
astraxan [27]
The answer is B.

14 + 15x
14 + 15(5)
14 + 75
89
7 0
3 years ago
Read 2 more answers
Please helpppppppppppp
lions [1.4K]

for A is-48
nd B is-16.5
nd C is-32.4
8 0
3 years ago
D + -4 = 12<br>how do i find d?​
abruzzese [7]

Answer: D=16

Add 4 to both sides

D=16

8 0
3 years ago
Read 2 more answers
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