Question

The two triangles below are similar. Triangle A B C. Side A B is 4 centimeters and B C is 9 centimeters. Angle A is 104 degrees, B is 50 degrees, C is 26 degrees. Triangle A prime B prime C prime. Side A prime B prime is 2 centimeters and B prime C prime is 4.5 centimeters. Angle A prime is 104 degrees, B prime is 50 degrees, C prime is 26 degrees. What is the ratio of the corresponding side lengths? 4:9 4:2 26:26 4.5:2

Answer 1

Answer:

4 : 2

Step-by-step explanation:

The two triangles Δ ABC and Δ A'B'C' are similar.

Here, ∠ A = ∠ A' = 104°, ∠ B = ∠ B' = 50° and ∠ C = ∠ C' = 26°.

Now, the length of AB and the length of A'B' are 4 cm and 2 cm respectively.

Again, the length of BC and the length of B'C' are 9 cm and 4.5 cm respectively.

Therefore, $\frac{AB}{A'B'} = \frac{BC}{B'C'} = \frac{CA}{C'A'} = \frac{4}{2} = \frac{9}{4.5} = 2$

Hence, the ratio of the corresponding side lengths is 4 : 2. (Answer)

Answer 2

Answer:

4:2

Step-by-step explanation: