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joja [24]
3 years ago
13

In order to pay for his expenses Chuck needs to earn $3,400 at least every month when Chuck Works overtime he earns $5000 per mo

nth if the variable T stands for the amount of money Chuck has left after paying for his expenses every month, which of the following choices is the most reasonable value for e when he works overtime
A. $600
B. $1600
C. 1200
D.$8400
Mathematics
2 answers:
Anna35 [415]3 years ago
6 0
The answer is B. $1600 because you have to subtract it
Minchanka [31]3 years ago
5 0

Answer:

<h2>B.  $1,600</h2><h2 />

Step-by-step explanation:

$3,400 + T = $5,000

T = $5,000 - $3,400

T = $1,600

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An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand
Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

b) We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

Part b

We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

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3 years ago
A store pays $423 for a crystal vase and marks the price up by 46%. What is the amount of the mark-up?
jek_recluse [69]

Answer:

194.58$

Step-by-step explanation:

Have a great day! :)

6 0
3 years ago
Read 2 more answers
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lord [1]

Range = -4= g(x)

Therefore, g(x) = -3x+2

or, -4=3x +2

or, 3x= -4-2

or, 3x= -6

or, x= -6/3 = -2

OPTION A is the correct answer.

4 0
3 years ago
Can someone help me with this math homework please!
Lera25 [3.4K]

Answer:a c b

c

Step-by-step explanation: did it already

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