Answer:
On problem one the answer is 4 but I'm not sure about the second problem
Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
Answer:
slope = - 3 y-intercept = 36
Step-by-step explanation:
12x + 4y = 144 , will allow this to be done.
so 4y = - 12x + 144
now dividing both sides of the equation by 4 will give
y = - 3x + 36 , which is now in the required form
slope = - 3 and y-intercept = 36
