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leva [86]
3 years ago
6

What transformations was not done to the linear parent function, f(x)=x to get the function g(x)=-1/3(x-7)+2?

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0

Answer:

Step-by-step explanation:

Consider that by changing the the variable x with x-c represents a horizontal shift of c units. If c>0 then it is a right shift and it is a left shift otherwise. When we multiply the variable by a number d (i.e dx) we are applying an horizontal compression/stretching. If d>1 it compresses it, and if 0<d<1 it stretches it. By multipyling the variable x by a negative sign, we are reflecting with respect the x -axis. Finally when we add a number to the function, we are applying a vertical shift.

original function x.

1. (x-7): horizontal shift of 7 units to the right.

2. 1/3(x-7): Horizontal stretching by factor 1/3.

3.-1/3(x-7): Reflection with respect the x-axis

4.-1/3(x-7)+2: Vertical shift of two units up.

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For this case we have the following apple picking options, in dozens:

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ANswer:

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Answer:

Step-by-step explanation:

Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.

From the question, we can tell it is a inversed-cone (upside down)

Volume of Cone = \pi r^{2} \frac{h}{3}

a) Given Diameter , d = 15.5cm and Length , h = 350cm,

we first find the radius.

r = \frac{d}{2} \\=\frac{15.5}{2} \\=7.75cm

We will now find the volume of the cone.

Volume of cone  \pi (7.75)^{2} \frac{350}{3} \\= \frac{168175\pi }{24}

We know the density of ice is 0.93 grams per 1cm^{3}

1cm^{3} =0.93g\\\frac{168175\pi }{24}  cm^{3} =0.93(\frac{168175\pi }{24} )\\= 20473 g(Nearest Gram)

b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm

and the new length, h = 350cm - 15cm = 335cm

Now we will find the volume of this newly-shaped cone.

Volume of cone = \pi (7.4)^{2} \frac{335}{3} \\= \frac{91723\pi }{15} cm^{3}

Volume of cone being melted = New Volume - Original volume

= \frac{168175\pi }{24} -\frac{91723\pi }{15} \\= \frac{35697\pi }{40} cm^{3}

c) Lets take the bucket as a round cylinder.

Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.

Volume of cylinder = \pi r^{2} h\\=\pi (12.5)^{2} (30)\\=\frac{9375\pi }{2} cm^{3}

To overflow the bucket, the volume of ice melted must be more than the bucket volume.

Volume of ice melted after 5 hours = 5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}

See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.

Volume of bucket - Volume of ice melted after 5 hours

= \frac{9375\pi }{2} -\frac{35697\pi }{8 } \\=\frac{1803\pi }{8}cm^{3}

from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.

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Answer:

n = 0.15(180)

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