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Rom4ik [11]
3 years ago
10

A newsletter publisher believes that above 41A% of their readers own a personal computer. Is there sufficient evidence at the 0.

100.10 level to substantiate the publisher's claim?
Mathematics
1 answer:
klemol [59]3 years ago
6 0

Complete Question

A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?

State the null and alternative hypotheses for the above scenario.

Answer:

The null hypothesis is  H_o  : p \le   0.411

The  alternative hypothesis  is  H_a : \mu >  0.41

Step-by-step explanation:

From the question we are told that

   The  proportion is  p  =  0.41

Generally the null hypothesis is  H_o  : p \le   0.411

The  above condition represents the  null hypothesis because it contains and equality in its condition

  The  alternative hypothesis  is  H_a : \mu >  0.41

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Maurinko [17]

Answer Difference between the experimental and the theoretical probability is 2/5 . Step-by-step explanation: Spinner is spun 10 times, and experimental probability of landing on a 3 is 1/2, i.e. out of 10 times spinner lands 5 times into 3.

I hope it is helpful

6 0
3 years ago
Which word correctly describes the pentagon?
Lina20 [59]
Equilateral correctly describes pentagon
7 0
3 years ago
Read 2 more answers
Mason walked on Monday, Wensday, and Friday. Use these clues to find how far he walked each day. These distances were six-eights
krok68 [10]

Answer:

Monday he walked \frac{1}{4}miles

Wednesday he walked \frac{6}{8}miles

Friday he walked \frac{1}{6}miles

Step-by-step explanation:

Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.

distances are \frac{6}{8}, \frac{1}{4}, \frac{1}{6} that are 0.75, 0.25 and 0.17 respectively.

Now, he didn't walk farthest on Monday and also walked less on Friday than Monday.

∴ Less distance travelled is \frac{1}{6} which is on friday and then \frac{1}{4} on monday.

Rest distance which is \frac{6}{8} on wednesday.

Hence, Monday he walked \frac{1}{4}miles

Wednesday he walked \frac{6}{8}miles

Friday he walked \frac{1}{6}miles

4 0
3 years ago
Read 2 more answers
In an experiment, the initial temperature of a solution is -5 °C. The solution is heated up at 3 °C per minute for 19 minutes an
Free_Kalibri [48]

Answer:

28°C

Step-by-step explanation:

First you do 3*19=57°C

-5+57= 52°C

then you do 4*6=24 °C

as its being cooled you takeaway

52-24=28°C

3 0
3 years ago
The height of a triangular prism is 6 cm and its base is an equilateral triangle with an area of 25 sq cm. Find the volume of th
NARA [144]

Answer:

150cm³

Step-by-step explanation:

volume =1/2b×bh×h

volume=25×6

=150

hope this helps

please like and Mark as brainliest

6 0
3 years ago
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