-2 (3y + 5) = -4
3y + 5 = -4 / -2
3y + 5 = 2
3y = 2 - 5
3y = -3
y = -1
5y = (-1)*5
5y = -5
(2x10^3) x (4x10^4) = 8x10^1
From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;
F = ma
In this case, m = 5kg, a = 6m/s^2 and we want to find F
F = 5 x 6
F = 30N
Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.
