Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
Answer:
3.6
Step-by-step explanation:
hey, how this helps and is right haha
c) 1 week x 7 days/1 week x 24hr/1 day x 60min/1hr x 60s/1min =
If you solved it, you would get 604,800, which is correct.
Answer: 5x+3y=-18
Step-by-step explanation:
