Answer:
46 mph and 61 mph
Step-by-step explanation:
Distance=speed*time
Let speed of one bus be x and another x+15
After 3 hours
First bus would have traveled 3x while second bus 3(x+15)=3x+45
Total distance= 3x+3x+45=6x+45
6x+45=321
6x=321-45=276
x=276/6=46 mph
x+15=46+15=61 mph
20 possibilities based on this as a combination not a permutation, 6 nCr 3 = 20
V=hpir^2
d/2=r
5/2/2.5
h=7
V=7pi2.5^2
v=7pi6.25
V=43.75pi
aprox pi=3.141592
V=137.44465
V=43.75pi ft^3 or aprox 137.44465 ft^3
Answer:
10x+13y
Step-by-step explanation:
remove parentheses:
2x+3y+8x+10y
add like-terms:
2x+8x+3y+10y
add numbers with the same variables/elements
10x+3y+10y-->10x+13y
hope this helps
