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Vaselesa [24]
3 years ago
11

A car owner may buy insurance that will pay the full price of repairing the car after an at-fault accident, or save $12 a year b

y getting a policy with a $500 deductible. Her insurance company says that about 0.5% of drivers in her area have at-fault auto accidents during any given year. Based on this information, should she buy the policy with the deductible or not? How does the value of her car influence this decision?
Mathematics
1 answer:
Andrej [43]3 years ago
6 0

Answer:

Step-by-step explanation:

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5

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How does the jet stream affect weather around the world? For 100 points!!!
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7 0
4 years ago
State University uses thousands of fluorescent light bulbs each year. The brand of bulb it currently uses has a mean life of 600
Ipatiy [6.2K]

Answer:

The test statistic is t = 2.5.

The p-value of the test is of 0.007 < 0.05, which means that the evidence supports the manufacturer's claim at the .05 significance level.

Step-by-step explanation:

Mean life of 600 hours. Test if it is more.

At the null hypothesis, we test if the mean is of 600 hours, that is:

H_0: \mu = 600

At the alternative hypothesis, we test if the mean is of more than 600 hours, that is:

H_1: \mu > 600

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

600 is tested at the null hypothesis:

This means that \mu = 600

Suppose 100 bulbs were tested and found to have a mean of 625 hours with a standard deviation of 100.

This means that n = 100, X = 625, s = 100.

Value of the test-statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{625 - 600}{\frac{100}{\sqrt{100}}}

t = 2.5

The test statistic is t = 2.5.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 625 hours, which is a right-tailed test, with t = 2.5 and 100 - 1 = 99 degrees of freedom.

Using a t-distribution calculator, this p-value is of 0.007.

The p-value of the test is of 0.007 < 0.05, which means that the evidence supports the manufacturer's claim at the .05 significance level.

4 0
3 years ago
I need a lot of help with this question!!!!!!<br><br>CLICK THE PICTURE
malfutka [58]
I need a lot of help with this question!!!!!!

CLICK THE PICTURE


The x is going to =7.5 i belive is right
8 0
3 years ago
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