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Shalnov [3]
3 years ago
9

The sum of two integers is 9 and the sum of their squares is 53. Find the integers.

Mathematics
1 answer:
Schach [20]3 years ago
6 0
X + y = 9 Subtract x from both sides.
y = 9 - x

x^2 + y^2 = 53
x^2 + (9 - x)^2 = 53 Remove the brackets.
x^2 + 81 - 18x + x^2 = 53 Collect the like terms on the left.
2x^2 - 18x + 81 = 53 Subtract 53 from both sides.
2x^2 - 18x + 81 - 53 = 0
2x^2 - 18x + 28 = 0 This factors, but you can see it much easier if you pull out 2 as a common factor.
2(x^2 - 9x + 14) = 0
2(x - 2)(x - 7) =0 You could divide by 2 on both sides. But you can also leave it.
x - 2 = 0
x =  2
x - 7 = 0
x = 7
If x = 2 then y = 7
If x = 7 then y = 2
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Answer:

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Step-by-step explanation:

Given

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Required

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Open bracket

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Let

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So:

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V = \frac{99}{7} x^{9}y^{-6}

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