It looks like you're asked to find the value of y(-1) given its implicit derivative,

and with initial condition y(2) = -1.
The differential equation is separable:

Integrate both sides:


Solve for y :



![y = -\dfrac1{\sqrt[3]{3x+C}}](https://tex.z-dn.net/?f=y%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3x%2BC%7D%7D)
Use the initial condition to solve for C :
![y(2) = -1 \implies -1 = -\dfrac1{\sqrt[3]{3\times2+C}} \implies C = -5](https://tex.z-dn.net/?f=y%282%29%20%3D%20-1%20%5Cimplies%20-1%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3%5Ctimes2%2BC%7D%7D%20%5Cimplies%20C%20%3D%20-5)
Then the particular solution to the differential equation is
![y(x) = -\dfrac1{\sqrt[3]{3x-5}}](https://tex.z-dn.net/?f=y%28x%29%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3x-5%7D%7D)
and so
![y(-1) = -\dfrac1{\sqrt[3]{3\times(-1)-5}} = \boxed{\dfrac12}](https://tex.z-dn.net/?f=y%28-1%29%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3%5Ctimes%28-1%29-5%7D%7D%20%3D%20%5Cboxed%7B%5Cdfrac12%7D)
A and F are true. because A is y=2x+7, and F is y=2x+7.
We know that the equation y=2x+7 has a point 0,7 and with the slope being 2, rise over run would make another point 1,9. And because these are linear equations if the equation y=2x+7 goes through 1,9 then it will go though -2,3 as well.
Answer:
the answer is. .6xy..........
Answer:
D
Step-by-step explanation:
if you have 37 and however many you eat you subtract from that 37 giving you R
Answer:

Step-by-step explanation:

So, 
= 
Hope this helps :)