Let 'x' be the problems worth 2 points.
Let 'y' be the problems worth 3 points.
Since, there are 38 total problems.
So, 
(equation 1)
x = 38-y
Since, a perfect score is 100 points.
So, 
(equation 2)
Substituting the value of 'x', we get
y = 24
x+y = 38
x = 38-24 = 14
So, 14 problems are worth 2 points and 24 problems are worth 3 points.
To solve for this, we need to figure out the sum of any two numbers on the dice that will become a pair factor for the listed answers.
What I mean by that is that we need to find the probability between how many two numbers will sum up to the answer.
3 can be 1 + 2, that's it. 3 has a probability of (1).
4 has a sum of 1 + 3, and 2 + 2, that's it. 4 has a probability of (2).
7 has a sum of 1 + 6, 2 + 5, and 3 + 4. 7 has a probability of (3).
11 has a sum of 5 + 6, that's it. 11 has a probability of (1).
The numbers in parenthesis are the probabilities.
7 has the highest number, so 7 has the highest probability.
Your answer is: 7.
I hope this helps!
Answer:
19.5
Step-by-step explanation:
The 43rd term of the sequence is 19.5
Answer: B
Step-by-step explanation:
