3 years ago

Find the eighth term of P.G 1,2,4,8

2 answers:

3 0

$a_n=2^{n-1}\\\\a_1=2^{1-1}=2^0=1\\\\a_2=2^{2-1}=2^1=2\\\\a_3=2^{3-1}=2^2=4\\\\a_4=2^{4-1}=2^3=8\\\vdots\\a_{8}=2^{8-1}=2^7=128$

MAVERICK [17]3 years ago

3 0

the answer is 128, the pattern is multiplying the previous number by 2 so example: 2x2=4 4x2=8 etc.

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By the recursive definition,

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Read 2 more answers

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OverLord2011 [107]

I believe the answer is 5x

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3 years ago

melisa1 [442]

Answer:

$\boxed{\sf 10}$

Step-by-step explanation:

The additive number of any number is the number when added to the number gives a result of zero.

So, if we add 10 to -10 we get a result of zero.

=> -10+10

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3 years ago

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elena-14-01-66 [18.8K]

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2 years ago

Edna decided to purchase a $15,000 MSRP vehicle at a 5% interest rate for 3 years. The dealership offered her a $1500 cash-back

Ad libitum [116K]

P = A/D, Where P = Monthly payments, A = Total amount owed = 15,000-1,500 = $13,500,

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Therefore,
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3 years ago