Answer: The width of member is as follows: b = 3 ft
b = 3 × 12 in.
b= 36 in. The depth of member is as follows:
d = 8 ft
d = 8 × 12 in.
d=96 in. Since the structure used is Douglas fir-Larch lumber of size 3 × 8 size. Hence, tensile strength, f =1000 psi Calculate the net area of the member as follows: A = (b - ∅) × d
A= (36 - 7/8) × 96 Calculate the maximum axial tensile load by ASD method as follows: P = f × A
Im not too sure but I think its 4.6,because 1 in :.5 mile. As a whole, .5 can go into 2, 4 times, then whats left over also gets divided into .6. Add those together and youll get 4.6