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aleksley [76]
3 years ago
9

After receiving his allowance, Spencer spent half of it on a Mother’s Day card. He bought two toy cars for $.49 each to give to

his brothers, and a pack of gum for $.35. How much did Spencer receive for his allowance if $.42 is left over? (Please give equation and answer)
Mathematics
1 answer:
Lynna [10]3 years ago
7 0
.49(2)+0.35+0.42= $1.75
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five people, each working 8 hours a day, can assemble 400 toys in a five day work week. what is the average number of toys assem
vladimir1956 [14]

The question asks for the rate of toys per hour.

So we shall divide the total toys assembled by the total hours.

Its a five day week.

The number of hours allotted per day are 8.

So total allotted during the week are 8 × 5 = 40 hours.

Number of toys made during the week are 400.

Hence the number of toys assembled per hour per person

= number of toys / number of hours

= 400 / 40

= 10 toys per hour per person.

The average number of toys assembled per hour per person is 10.


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3 years ago
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Vitek1552 [10]

the constant term is 12

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3 years ago
What’s the multipcative inverse of 1/4
LuckyWell [14K]

Hey!

Answer:

4/1

Step-by-step explanation:

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Hope This Helps :)

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Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

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3 years ago
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