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Yuliya22 [10]
3 years ago
12

132 students for 6 classes

Mathematics
1 answer:
NeTakaya3 years ago
5 0

Answer:

22 students per class

Step-by-step explanation:

132/ 6= 22

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Determine the center and radius of the following circle equation:
UkoKoshka [18]

Answer:

The equation of the circle  <em>(x + 5 )² + ( y + 10 )² = (4)²</em>

<em>Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle     ' r' = 4</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given circle equation is x² + y² +10 x + 20 y +109 =0

                                     x² +10 x +  y² + 20 y +109 =0

  x² +2 (5) (x)+(5)² -(5)²+ y² +2(10) y + (10)²-(10)² +109 =0

<em>By using formula </em>

<em>(a+b)² = a² + 2 a b + b²</em>

<em>(x + 5 )² + ( y + 10 )² - 25 - 100 + 109 = 0</em>

<em>(x + 5 )² + ( y + 10 )² - 16 = 0</em>

<em>(x + 5 )² + ( y + 10 )² = 16</em>

(x + 5 )² + ( y + 10 )² = (4)²

The standard equation of the circle  ( x - h )² + ( y -k)² = r²

<em> Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle     ' r' = 4</em>

<u><em>Conclusion</em></u><em>:-</em>

The equation of the circle  <em>(x + 5 )² + ( y + 10 )² = (4)²</em>

<em>Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle     ' r' = 4</em>

<em></em>

3 0
3 years ago
What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
3 years ago
Read 2 more answers
Two perpendicular lines intersect at the origin. If the slope of the first line is .5, what is the equation of the second line?.
Sedaia [141]
The origin is at the point (0,0). Therefore, the y-intercept will be 0. For two points to be perpendicular, the slopes must be opposite reciprocals of each other. .5 can be seen as 1/2, so the reciprocal is 2, and it is positive, making that 2 negative. Your equation would be y = -2x. 
3 0
3 years ago
Beth filled 8 jars with paint.
sergey [27]

Answer:

Beth used 1 gallon of paint

Step-by-step explanation:

1 pint x 8 jars = 8

if 1 pint = 0.125 gallons,

0.125 x 8 would equal 1

this means that 8 pints of paint, would equal 1 gallon of paint.

5 0
3 years ago
Read 2 more answers
How do you do this?
Nat2105 [25]
U just need to add row by row
I'll do the first 1: 1+1=2
1+2=3
1+3=4
1+4=5
1+5=6
3 0
3 years ago
Read 2 more answers
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