150%. since you already have 6, that's 100%. the extra 3 is half of the 6, meaning that it would be 50%
Answer:
23°
Step-by-step explanation:
Step 1:
< GEC + < ECG + < CGE = Δ ECG Sum of a Δ
Step 2:
< IGF = < GCE Corresponding ∠ 's
Step 3:
14° + 180° - 4x + 78° = 180° Substitution
Step 4:
272° - 4x = 180° Add / Algebra
Step 5:
- 4x = - 92 Subtract 272° on both sides
Step 6:
- 92 ÷ - 4 Divide
Answer:
x = 23°
Hope This Helps :)
Answer:
It is not a function
Step-by-step explanation:
The plot shows (1, 1) and (1, 3) are both defined by the relation. It does not pass the "vertical line test", which requires the relation be single-valued everywhere.
Answer:
5x+10
Step-by-step explanation:
Hope this helps!!! :))
<span>1) if 2 times the wind speed is increased by 2, the wind speed is still less
than 46 km/h.
=> 2x + 2 < 46
2) Twice the wind speed minus 27 is greater than 11 km/h.
=> 2x - 27 > 11
Part A: Create a compound inequality to represent the wind speed range.
(3 points)
from 2x + 2 < 46
=> 2x < 44
=> x < 22
from 2x - 27 > 11
=> 2x > 11 + 27
=> 2x > 38
=> x > 19
The set of inequalities is
2x + 2 <46
2x - 27 > 11
The solution is x < 22 and x > 19, which is:
19 < x < 22 <----- answer
Part B: Can the wind speed in this town be 20 km/h? Justify
your answer by solving the inequalities in Part A. (3 points)
Yes, the wind speed can be 20 km/h, because the solution of the inequality is the range (19,22).
Part C:
The average wind speed in another town is 23 km/h, but the actual wind
speed is within 4 km/h of the average. Write and solve an inequality to
find the range of wind speed in this town.
x ≥ 23 - 4 => x ≥ 19
x ≤ 23 + 4=> x ≤ 27
=> 19 ≤ x ≤ 27
=> [19,27]
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