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cricket20 [7]
3 years ago
14

Write a formula for the distance between a point (x, y) on the graph of y = x^4 and the point (1, 10). Express your answer in te

rms of x.
Mathematics
1 answer:
blsea [12.9K]3 years ago
8 0
Anonymous's answer is completely correct. I thought this problem was asking how to find the distance along the function from the point (2,2^8), and wrote the answer to that nice, tasty problem.

Simply integrate the line element with respect to some affine parameter!

<span><span>L=<span>∫10</span><span><span><span><span>(<span><span>∂x</span><span>∂λ</span></span>)</span>2</span>+<span><span>(<span><span>∂y</span><span>∂λ</span></span>)</span>2</span></span><span>−−−−−−−−−−−−−</span>√</span>dλ</span><span>L=<span>∫01</span><span><span><span>(<span><span>∂x</span><span>∂λ</span></span>)</span>2</span>+<span><span>(<span><span>∂y</span><span>∂λ</span></span>)</span>2</span></span>dλ</span></span>

In this case,
<span><span>x(λ)=λ(X−2)+2,</span><span>x(λ)=λ(X−2)+2,</span></span>
<span><span>y(λ)=(λ(X−2)+2<span>)8</span>.</span><span>y(λ)=(λ(X−2)+2<span>)8</span>.</span></span>

<span>Note that this approach can also solve the original problem, with some simplification.</span>
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Help! Based on the given information, what can you conclude and why?
DochEvi [55]

Answer: \triangle HIJ \cong \triangle LKJ

Step-by-step explanation:

Given: ∠H ≅∠L and line HJ congruent to Line JL.

Since, In triangles HIJ and LKJ,

∠H ≅ ∠L

HJ ≅ JL

And, ∠HJI ≅ ∠ LJK

Therefore, By ASA postulate,

Δ HIJ ≅ Δ LKJ

This is why Option first is correct.

Note: Option third ΔHIJ≅ΔJKL is not correct,

Because,  HI≠JK



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You’re given two side lengths of 6 centimeters and 9 centimeters. Which measurement can you use for the lengths of the third sid
Vadim26 [7]

If we have a triangle with sides a,b,c then

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a = 6

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9-6 < c < 9+6

3 < c < 15

<h3>Answer: The third side is between 3 cm and 15 cm. The third side cannot equal 3 cm, and it also cannot equal 15 cm. </h3>
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3 years ago
What is $2.30 divided by 27?
Firlakuza [10]

Answer:33 cents

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its 0.328571429, but since its money, u can only go to the hundredths place, so u round up to 0.33

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Vitek1552 [10]
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