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3 years ago

Noor wants to spend less than $20 on condiments. Each kilogram of salt costs $1.50, and each kilogram of pepper costs 2.50.

Mathematics

1 answer:

nata0808 [166]3 years ago

3 0

Answer:

1.5s+2.5p<20

Step-by-step explanation:

Multiply by each kilo and then make sure it adds up to less than 20!

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How to write the rule 4,-4,-12,-20 going to a20

maks197457 [2]

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2 years ago

25, 8, 10, 35, 5, 45, 40, 30, 20 What is the upper quartile of the data set above?A.35

Vlada [557]

<span>An upper quartile is the range of numbers above the median in a set. Thus, the numbers have to be rearranged mentally or on paper. Fortunately, there are an odd set of numbers, so one number, 25, is the median. The upper quartile is 30, 35, 40, 45.</span>

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2 years ago

one tank is filling at a rate of 3/4 per gallon per 2/3 minute .a second tank is at a 5/8 gallon per 1 half gallon per 1/2 minut

Bingel [31]

$recall\ that\implies \cfrac{\frac{a}{b}}{\frac{c}{{{ d}}}}\implies \cfrac{a}{b}\cdot \cfrac{{{ d}}}{c}\qquad thus
\\ \quad \\

\cfrac{\frac{3g}{4}}{\frac{2m}{3}}\implies \cfrac{3g}{4}\cdot \cfrac{3}{2m}\implies \cfrac{\square ?}{\square ?}
\\-------------\\
\cfrac{\frac{5g}{8}}{\frac{1m}{2}}\implies \cfrac{5g}{8}\cdot \cfrac{2}{1m}\implies \cfrac{\square ?}{\square ?}$

so... you tells us, which filling rate is the bigger and thus faster one?

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3 years ago

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

$336.04 < \mu < 443.96$

The margin of error will increase

The margin of error will decreases

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

4 0

3 years ago

What is the vertex of y<∣x−3∣+5

Tcecarenko [31]

Answer:

(3, 5)

Step-by-step explanation:

The graph is is the standard y=|x| except the values tells you that x shifts 3 (within the absolute value or parentheses x does the opposite) to the right and the y value shifts 5 up (numbers outside parentheses affects y and does what it says). You can try using a table of values then graphing to check your answer.

3 0

2 years ago