Ask question

Ask question

All categories

3 years ago

8

Suppose that you are taking a T/F exam and you have no idea at all about the answers to the last three questions. You choose ans

wers randomly and therefore have a 50/50 chance of being correct on any one question. 1) what is the probability that you guessed right on exactly one of the three questions? [a] 2) what is the probability that you guessed right on zero of the three questions? [b] 3) what is the probability that you guessed right on at least two of the questions? [c]

1 answer:

podryga [215]3 years ago

7 0

Answer:

0.375, 0.125, 0.5

Step-by-step explanation:

given that you are taking a T/F exam and you have no idea at all about the answers to the last three questions.

Probability for correct guess = 0.5 remains constant for each of the three questions

X - no of questions is binomial with n =3 and p = 0.5

1) the probability that you guessed right on exactly one of the three questions

= P(X=1)

= $3C1(0.5)^3 = 0.375$

2) the probability that you guessed right on zero of the three questions

= $P(X=0)\\= 0.5^3=0.125$

3) the probability that you guessed right on at least two of the questions

= $P(x=3)+P(2)\\= 1-0.5\\=0.5$

You might be interested in

500 divide 10/2 and divide 5 and times x divide 5

coldgirl [10]

(500 / (10/2) / 5 ) * x / 5 = 20 * x / 5 = (20 / 5) * x = 4 * x

3 0

3 years ago

Solve this using a number line.<br> 3 1/8 ÷ 1/8

sp2606 [1]

Hey there!!

25 is the answer

Hope this helps. c:

4 0

3 years ago

Daisy is building a rectangular pen for her chickens along one wall in her back yard. She needs to build a fence

frosja888 [35]

Answer:

Daisy has one side of the rectangular pen along the wall, so she needs one width, w, and two lengths, 2ℓ. She has at most 125 feet of fencing materials to build the fence for her pen

1 second/24 frames

so if he started with 0 frames

time s = (1/24) (additional f)

but he already had at least 250 frames

so

time s = (1/24)( f-250) or maybe less time if he had more than 250

24 s </= f - 250

or

f >/= 24 s + 250

Step-by-step explanation:

7 0

3 years ago

What would the answer be for this equation 7x/20 - 5x/12

polet [3.4K]

Answer:

$\frac{1}{15} x$

Step-by-step explanation:

$\frac{7x}{20} - \frac{5x}{12}$

$\frac{3 \times 7x}{3 \times 20} - \frac{5 \times 5x}{5 \times 12}$

$\frac{21x}{60} - \frac{25x}{60}$

$\frac{21x - 25x}{60} = (21 - 25)x = - 4x$

$\frac{ - 4x}{60} = - \frac{ x}{15}$

$\boxed{\green{= \frac{1}{15} x}}$

4 0

2 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0

2 years ago