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kotegsom [21]
3 years ago
8

Suppose that you are taking a T/F exam and you have no idea at all about the answers to the last three questions. You choose ans

wers randomly and therefore have a 50/50 chance of being correct on any one question. 1) what is the probability that you guessed right on exactly one of the three questions? [a] 2) what is the probability that you guessed right on zero of the three questions? [b] 3) what is the probability that you guessed right on at least two of the questions? [c]
Mathematics
1 answer:
podryga [215]3 years ago
7 0

Answer:

0.375, 0.125, 0.5

Step-by-step explanation:

given that you are taking a T/F exam and you have no idea at all about the answers to the last three questions.

Probability for correct guess = 0.5 remains constant for each of the three questions

X - no of questions is binomial with n =3 and p = 0.5

1) the probability that you guessed right on exactly one of the three questions

= P(X=1)

= 3C1(0.5)^3 = 0.375

2) the probability that you guessed right on zero of the three questions

= P(X=0)\\= 0.5^3=0.125

3) the probability that you guessed right on at least two of the questions

=P(x=3)+P(2)\\= 1-0.5\\=0.5

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Not sure what figure you are referring to, write an equation from the given values:

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:

:

That you can also see the original value of the phone card: x=0, y = $30

;

:

Did this help you understand what's going on here? Any questions

Step-by-step explanation:

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