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vladimir2022 [97]
3 years ago
15

Solve the equation show your work 3x equals 45​

Mathematics
2 answers:
natima [27]3 years ago
7 0

Answer:

x = 15

Step-by-step explanation:

3x / 3 = 45 / 3 x = 15

PilotLPTM [1.2K]3 years ago
3 0

3x = 45

We have to isolate x. To do that we must bring 3 to the right side of the equation.

How is that done?

Well you need a little bit of magic. Just kidding, you need something close to it. It's called math

Since three is being multiplied by x we have to do the opposite of multiplication to bring it over to the right side and cancel 3 from the left side. The opposite of multiplication is DIVISION so...

3x ÷ 3 = 45 ÷ 3

^^^What you do to one side you do to the other

x = 15

Hope this helped!

~Just a girl in love with Shawn Mendes

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A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou
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Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let z be the

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question, x = 5 and \sigma = 2. The equation becomes

\displaystyle z = \frac{5 - \mu}{2}.

To solve for \mu, the mean of this distribution, the only thing that needs to be found is the value of z. Since

The problem stated that P(X \le 5) = 69.85\% = 0.6985. Hence, P(Z \le z) = 0.6985.

The problem is that the normal distribution tables list only the value of P(0 \le Z \le z) for z \ge 0. To estimate  z from P(Z \le z) = 0.6985, it would be necessary to find the appropriate

Since P(Z \le z) = 0.6985 and is greater than P(Z \le 0) = 0.50, z > 0. As a result, P(Z \le z) can be written as the sum of P(Z < 0) and P(0 \le Z \le z). Besides, P(Z < 0) = P(Z \le 0) = 0.50. As a result:

\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}.

Therefore:

\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}.

Lookup 0.1985 on a normal distribution table. The corresponding z-score is 0.52. (In other words, P(0 \le Z \le 0.52) = 0.1985.)

Given that

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  • x =5, and
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Solve the equation \displaystyle z = \frac{x - \mu}{\sigma} for the mean, \mu:

\displaystyle 0.52 = \frac{5 - \mu}{2}.

\mu = 5 - 2 \times 0.52 = 3.96.

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