3 years ago

What values of b satisfy 4(3b + 2)2 = 64?

1 answer:

8 0

Given the equation 4(3b + 2)² = 64, dividing both sides of the equation by 4, we have (3b + 2)² = 16 and getting the square root of both sides, (3b + 2) = 4 and (3b + 2) = -4 We can solve for b for each equation and have 3b = 2 | 3b = -6 b = 2/3 | b = -2 Therefore, the values of b are 2/3 and -2 and from the choices, the answer is A: b = 2/3 and b = -2.

You might be interested in

DG¯¯¯¯¯¯ , EG¯¯¯¯¯ , and FG¯¯¯¯¯ are perpendicular bisectors of the sides of △ABC . DG=5 cm and BD=12 cm.

jonny [76]

Given that DG, EG, and FG are perpendicular bisectors of the sides of △ABC, this means that the point of intersection, G, is the circumcenter of the triangle and hence AG, BG, and CG are equal.

Given that DG = 5 cm and BD = 12 cm, then

$BG= \sqrt{DG^2+BD^2} \\ \\ = \sqrt{5^2+12^2} = \sqrt{25+144} \\ \\ = \sqrt{169} =13$

Since AG = BG = CG, therefore, CG = 13 cm.

3 0

3 years ago

7-(30-2) divided by 7 equals?

dybincka [34]

Answer:

Step-by-step explanation:

first, do 30-2 to get 28. 7-28 is -21. -21/7 is -3

6 0

3 years ago

Read 2 more answers

What is the slope if i only have the two points (9,8) and (3,4)

DIA [1.3K]