Answer:
Explanation:
Impulse on an object is given by ![\mathrm{[impulse]}=F\Delta t](https://tex.z-dn.net/?f=%5Cmathrm%7B%5Bimpulse%5D%7D%3DF%5CDelta%20t)
.
However, it's also given as change in momentum (impulse-momentum theorem).
Therefore, we can set the change in momentum equal to the former formula for impulse:
.
Momentum is given by 
. Because the truck's mass is maintained, only it's velocity is changing. Since the truck is being slowed from 26.0 m/s to 18.0 m/s, it's change in velocity is 8.0 m/s. Therefore, it's change in momentum is:
.
Now we plug in our values and solve:
(two significant figures).
Answer:
Airplane speed relative to the ground is 260 km/h and θ = 22.6º direction from north to east
Explanation:
This is a problem of vector composition, a very practical method is to decompose the vectors with respect to an xy reference system, perform the sum of each component and then with the Pythagorean theorem and trigonometry find the result.
Let's take the north direction with the Y axis and the east direction as the X axis
Vy = 240 km / h airplane
Vx = 100 Km / h wind
a) See the annex
Analytical calculation of the magnitude of the speed and direction of the aircraft
V² = Vx² + Vy²
V = √ (240² + 100²)
V = 260 km/h
Airplane speed relative to the ground is 260 km/h
Tan θ = Vy / Vx
tan θ = 100/240
θ = 22.6º
Direction from north to eastb
b) What direction should the pilot have so that the resulting northbound
Vo = 240 km/h airplane
Vox = Vo cos θ
Voy = Vo sin θ
Vx = 100 km / h wind
To travel north the speeds the x axis (East) must add zero
Vx -Vox = 0
Vx = Vox = Vo cos θ
100 = 240 cos θ
θ = cos⁻¹ (100/240)
θ = 65.7º
North to West Direction
The speed in that case would be
V² = Vx² + Vy²
To go north we must find Vy
Vy² = V² - Vx²
Vy = √( 240² - 100²)
Vy = 218.2 km / h
Answer:
<h3>The answer is 1600 kgm/s</h3>
Explanation:
The momentum of an object can be found by using the formula
<h3>momentum = mass × velocity</h3>
From the question
mass = 200 kg
velocity / speed = 8m/s
We have
momentum = 200 × 8
We have the final answer as
<h3>1600 kgm/s</h3>
Hope this helps you
Answer:
Explanation:
The period of oscillation is given as
T=2π√m/k
Making k subject of the formula
Square both sides of the equation
T²=4π²(m/k)
Cross multiply
T²k=4π²m
Then, divide through by T²
k=4π²m/T²
Where
k is spring constant
m is the mass of the bob
And T is the period of the oscillation
m=140g=0.14kg
14 oscillations takes 14 seconds
Then the period is
T=time/oscillation
T=14/14
T=1sec
Then,
k=4π²m/T²
k=4π²×0.14/1²
k=1.76N/m
Then, the spring constant is 1.76N/m
Answer:
-5.29 m/s
Explanation:
Given:
y₀ = 1.43 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2a (y − y₀)
v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.43 m)
v = -5.29 m/s
