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Anna [14]
3 years ago
7

Find the length of BC.

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
7 0

Answer: 10.25

Step-by-step explanation:

Use Pythagoras  equation:

AB=√AD²+BD²

AB=√5²+4²

AB=√25+16

AB=√41

cos∡ABC=AB/BC=BD/AB

AB/BC=BD/AB

AB²=BC*BD

(√41)²=BC*4

41/4=BC

BC=10.25

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Write and solve an equation to find the value of x and a missing angle in the triangle below.
Oksi-84 [34.3K]

Answer:

angle UTS +TSU =TUV

THEREFORE, 81 + 12X =24X+9

THEREFORE, 81 - 9 = 24X - 12X

THEREFORE, 72 = 12X

THEREFORE, 72/12 =X

THEREFORE, x = 6

THEREFORE, ANGLE TSU = 12 * X

= 12 *6

= 72

YOUR ANSWER IS

X=6

TSU=72

THANK YOU......

6 0
3 years ago
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Answer:

1. Likely.

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Step-by-step explanation:

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3 years ago
A 20 foot ladder leaning against a wall is used to reach a window that is 17 feet above the ground. How far from the wall is the
GarryVolchara [31]

The bottom of the ladder is 10.5 feet away from the wall

Step-by-step explanation:

The given scenario forms a right triangle.

Where

The length of ladder will be the hypotenuse

The wall on which the window is situated will ebt he perpendicular and

The distance between the foot of ladder and the wall will be the base

So,

Hypotenuse = H = 20 foot

Perpendicular = P = 17 feet

Base = B = ?

Using the Pythagoras theorem

H^2=P^2+B^2\\(20)^2=(17)^2+B^2\\400=289+B^2\\400-289=B^2\\B^2=111\\Taking\ square\ root\ on\ both\ sides\\\sqrt{B^2}=\sqrt{111}\\B=10.53\\Rounding\ off\ to\ the\ nearest\ tenth\\B=10.5

The bottom of the ladder is 10.5 feet away from the wall

Keywords: Triangle, Pythagoras Theorem

Learn more about Pythagoras theorem at:

  • brainly.com/question/9532142
  • brainly.com/question/9590016

#LearnwithBrainly

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3 years ago
Find values of x and y for which ABCD must be a parallelogram. The diagram is not to scale.
Artist 52 [7]
3x-14=x+2:4y-7=y+11\\2x=16:3y=18\\x=8:y=6

D. x=8, y=6
7 0
3 years ago
Look at the incomplete multiplication problem below.
alexdok [17]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
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