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Mandarinka [93]
4 years ago
14

Explain how you could use 25% of a number to find the number

Mathematics
1 answer:
Elenna [48]4 years ago
5 0

Answer:

you know 25% is one fourth of 100%, aka the whole number, so just multiply the 25% of the number times 4 to get the whole number

You might be interested in
I need help quickly!!!!
Mademuasel [1]
A) Yes, it starts with the same coordinates. because it start as (0,0)
B) No, it because it (6,3)
C) No, because the line segment goes higher and higher.
D) No, because the domain and range dont repeat.
E) I dont exactly know sorry :/
8 0
3 years ago
Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms oc
Anit [1.1K]

Answer:

a)\hat \sigma^2 =s^2 =30^2 = 900

b) 567.277 \leq \sigma^2 \leq 1690.224

Rounded to the nearest number would be:

567 \leq \sigma^2 \leq 1690

c) 23.818 \leq \sigma \leq 41.112

And rounded :

23.8 \leq \sigma \leq 41.1

Step-by-step explanation:

Data given and notation

s=30 represent the sample standard deviation

\bar x=290 represent the sample mean

n=20 the sample size

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Part a

The best point of estimate for the population variance is the sample variance, so on this case:

\hat \sigma^2 =s^2 =30^2 = 900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,19)" "=CHISQ.INV(0.95,19)". so for this case the critical values are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma \leq \frac{(19)(30)^2}{10.117}

567.277 \leq \sigma^2 \leq 1690.224

Rounded to the nearest number would be:

567 \leq \sigma^2 \leq 1690

Part c

In order to find the confidence interval for the deviation we just need to take the square root for the interval of the variance, and we got:

23.818 \leq \sigma \leq 41.112

And rounded :

23.8 \leq \sigma \leq 41.1

7 0
3 years ago
Can someone help me?
Alex17521 [72]

Answer:A

Step-by-step explanation:

4 0
3 years ago
Circle P has a circumference of approximately 75 inches.
Nookie1986 [14]

Answer:

The length of the radius is 12 in

Step-by-step explanation:

To solve this problem we need to use the circumferenc formula of a circle:

c = circumference  = 75in

r = radius

π = 3.14

c = 2π * r

we replace with the known values

75in = 2 * 3.14 * r

75in = 6.28 * r

75in / 6.28 = r

11.94in = r

round to the nearest inch

r = 11.94in = 12 in

The length of the radius is 12 in

4 0
3 years ago
Read 2 more answers
Area of irregular shape?​
slavikrds [6]

Answer:

106 sq. meters.

Step-by-step explanation:

Comment down if you need the complete explanation.

3 0
3 years ago
Read 2 more answers
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