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Bezzdna [24]
3 years ago
6

I'm confused on case 3 sea level

Mathematics
1 answer:
Ratling [72]3 years ago
4 0
Try 488 or 3050 but I think it is most likely 488.
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Mrs.Henderson had 7/12dozen eggs in her refrigerator.Then she used 1/6 dozen eggs to make a cake.What fraction of a dozen is lef
zhuklara [117]
Ok so to find the eggs left we need to subtract but with fractions, you need a common denominator. You can multiply 1/6 by 2 because 6·2=12 which will be the same denominator as 7/12. You must multiply the numerator by 2 as well so 1/6· 2/2= 2/12. Now subtract 7/12 - 2/12 and you have 5/12 eggs left. :)
5 0
2 years ago
Read 2 more answers
If bolt thread length is normally distributed, what is the probability that the thread length of a randomly selected bolt is Wit
KatRina [158]

Answer:

a) 0.5762

b) 0.0214

c) 0.2718

Step-by-step explanation:

It is given that lengths of the bolt thread are normally distributed. So in order to find the required probability we can use the concept of z distribution and z scores.

Part a) Probability that length is within 0.8 SDs of the mean

We have to calculate the probability that the length of a bolt thread is within 0.8 standard deviations of the mean. Recall that a z- score tells us that how many standard deviations away a value is from the mean. So, indirectly we are given the z-scores here.

Within 0.8 SDs of the mean, means from a score of -0.8  to +0.8. i.e. we have to calculate:

P(-0.8 < z < 0.8)

We can find these values from the z table.

P(-0.8 < z < 0.8) = P(z < 0.8) - P(z < -0.8)

= 0.7881 - 0.2119

= 0.5762

Thus, the probability that the thread length of a randomly selected bolt is within 0.8 SDs of its mean value is 0.5762

Part b) Probability that length is farther than 2.3 SDs from the mean

As mentioned in previous part, 2.3 SDs means a z-score of 2.3.

2.3 Standard Deviations farther from the mean, means the probability that z scores is lesser than - 2.3 or greater than 2.3

i.e. we have to calculate:

P(z < -2.3 or z > 2.3)

According to the symmetry rules of z-distribution:

P(z < -2.3 or z > 2.3) = 1 - P(-2.3 < z < 2.3)

We can calculate P(-2.3 < z < 2.3) from the z-table, which comes out to be 0.9786. So,

P(z < -2.3 or z > 2.3) = 1 - 0.9786

= 0.0214

Thus, the probability that a bolt length is 2.3 SDs farther from the mean is 0.0214

Part c) Probability that length is between 1 and 2 SDs from the mean value

Between 1 and 2 SDs from the mean value can occur both above the mean and below the mean.

For above the mean: between 1 and 2 SDs means between the z scores 1 and 2

For below the mean: between 1 and 2 SDs means between the z scores -2 and -1

i.e. we have to find:

P( 1 < z < 2) + P(-2 < z < -1)

According to the symmetry rules of z distribution:

P( 1 < z < 2) + P(-2 < z < -1) = 2P(1 < z < 2)

We can calculate P(1 < z < 2) from the z tables, which comes out to be: 0.1359

So,

P( 1 < z < 2) + P(-2 < z < -1) = 2 x 0.1359

= 0.2718

Thus, the probability that the bolt length is between 1 and 2 SDs from its mean value is 0.2718

4 0
3 years ago
julia and her friends are making kites out of paper. For each kite, they need a piece of paper that is \dfrac{65}{100} \text{ me
Alona [7]

Answer:

  260 cm

Step-by-step explanation:

Each 1/00 of a meter is 1 cm, so 65/100 meters is 65 cm. If that is the length of paper required for 1 kite, then 4 times that length will be required for 4 kites.

__

The paper required for 4 kites is ...

  (65 cm) × 4 = 260 cm

8 0
2 years ago
A cheetah ran 75 meters at a speed of 25 meters per second.How long was the cheetah running?
kenny6666 [7]
75 / 25 = 3  The Cheetah was running 3 sec
6 0
3 years ago
Read 2 more answers
Multiple by moving the decimal point 24.6x100,37x1,000 0.367x10,000,0.005x1000,000 .
lesya [120]

The answers are 2460, 37,000, 3670 and 5000

Step-by-step explanation:

  • Step 1: Find the answers for each by multiplying.

24.6 × 100 = 2460 (moved one decimal point)

37 × 1000 = 37,000

0.367 × 10000 = 3670 (moved three decimal points)

0.005 × 1000,000 = 5000 (moved three decimal points)

8 0
3 years ago
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