First one:
you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so
when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)
-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m
add
-10m-13m+2m^4-20m^4
-23m-18m^4
second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms
(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8
With all the stuff added together, the sum is 2.03 kg
Answer: y=kx/w^2
Step-by-step explanation:
y is directly proportional to x
y∝x
y=kx
y inversely proportional to the square of w.
y ∝ (1/(w)^2)
y=k/w^2
y=kx/w^2
Answer:
Option B is correct.
Step-by-step explanation:
We need to find the value of S in cos S = 0.9092
cos S = 0.9092
To find value of S we will find cos^-1(0.9092) i.e
S = cos^-1 (0.9092)
S = 24.6 °
So, the measure of the angle to the nearest tenth of a degree of cos S = 0.9092 is 24.6°
So, Option B is correct.
The vertical asymptote is r = 0. The intensity is undefined at the source. The horizontal asymptote is I = 0. As the distance from the source increases, the intensity goes to zero. The intensity decreases as the distance increases.
