Find the distance between the points given (3,4) (6,8)

What restrictions are there on the range of the function H(w) below?

Eddi Din [679]

The function, named H(w) is defined by a graph that is a descendant line, that belongs only to the first quadrant. As w approaches to 0 by the right, the function approaches to + infinity. It never touches the vetical axis, decreases and approaches to 0 when w approaches to infinity. The graph never touches the horizontal - axis.

Then, the function is defined only for positive values of w and H(w) is always positive.

Then, the answer is H(w) > 0, this is the option C.

5 0

3 years ago

Read 2 more answers

what is the completely factored form of t^4 − 16? (t^2 4)(t^2 − 4) (t^2 4)(t 2)(t − 2) (t^2 4)(t − 2)(t − 2) (t 2)(t 2)(t 2)(t −

Eva8 [605]

$Use:a^2-b^2=(a-b)(a+b)\\\\t^4-16=(t^2)^2-4^2=(t^2-4)(t^2+4)=(t^2-2^2)(t^2+4)=(t-2)(t+2)(t^2+4)$

7 0

3 years ago

The _______________ separates the region of rejection from the region of non rejection.

Alekssandra [29.7K]

Answer:

Critical Value

Step-by-step explanation:

The critical value separates the region of rejection from the region of non rejection.

We define critical values as:

Critical value helps us to give the decision rule for the rejection or acceptance of null hypothesis.
Critical value separates the acceptance region from the rejection region.
These are referred to as cut-off values that define regions where the test statistic is unlikely to lie.
The critical value depends on the kind of test being performed and the significance level.

6 0

3 years ago

SOLVE FOR M. please :)

STatiana [176]

Answer:

$m = - 28$

Step-by-step explanation:

$\frac{ - 3}{7} m = 12$

$\frac{ - 7}{3} ( \frac{ - 3}{7})m = \frac{ - 7}{3} \times 12$

$\frac{ - 1}{3} ( - 3)m = \frac{ - 7}{3} \times 12$

$- 1( - 1)m = \frac{ - 7}{3} \times 12$

$1 \times m = \frac{ - 7}{3} \times 12$

$m = \frac{ - 7}{3} \times 12$

$m = \frac{ - 7}{3} (3 \times 4)$

$m = - 28$

<h3>Hope it is helpful....</h3>

3 0

3 years ago

Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10

Vladimir [108]

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000 (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

5 0

3 years ago