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ArbitrLikvidat [17]
3 years ago
13

Solve the equation for the variable. Show all solving steps. –13m = –39

Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0
I'm unsure of how to explain this but -39 divided by -13 equals 3
M=3
ikadub [295]3 years ago
3 0
M=(-39/-13)
m=3

......
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Which table has a constant of proportionality between yyy and xxx of 101010?
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Answer:

Only table C shows proportional relationship

Step by Step Explanation:

Given

Tables A, B an C

Required

Which table shows proportional relationship?

In table A .

x = 2 and y = 20

k = 20/2

k = 10

Also, x = 12, y = 132

k =. 132/12.

k = 11

Both values of k are not equal.

Hence, the table is not proportional

In table B

x = 5 and y = 20

k = 20/5

k = 4

Also, x = 7, y = 30

k =. 30/7

k = 4.29

Both values of k are not equal.

Hence, the table is not proportional

In table C

x = 9 and y = 90

k = 90/9

k = 10

Also, x = 14, y = 140

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k = 10

Also, x = 24, y = 240

k =. 240/24

k = 10

All values of k are equal.

Hence, the table is proportional

5 0
3 years ago
Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

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