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denis23 [38]
3 years ago
5

Savings account A has $500 and pays 4% interest yearly. Savings account B

Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0

Answer:

The first one.

Step-by-step explanation:

Lets calculate the interest after one year.

1) 500 * (1.04) = 520

2) 600 * (1.025) = 615.

As you can tell the first one earned 20 dollars in the first year while the second one earned 15 dollars in the same year. This means that the first one has earned more interest.

Hope this helps.

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tangare [24]

Answer:

9 x (x +5) = 185

Step-by-step explanation:

I'm pretty sure this is how you write it

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Becky bought a magazine for $3.90, and the sales tax was 8.25%. How much sales tax did Becky pay on the magazine?
igor_vitrenko [27]

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32 cents

Step-by-step explanation:

Find 8.25 percent of 3.90:

0.0825*3.90 = 0.32

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Help me I need to get a 100
swat32

Answer:

option 2

Step-by-step explanation:

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3 years ago
A shopper bought a 12-pound bag of oranges for 18.75. What is the unit price per ounce?
noname [10]

Answer:

About $0.10 per ounce

Step-by-step explanation:

12 pound costs $18.75. Lets find the cost per pound first:

Cost Per Pound = \frac{18.75}{12}=1.5625

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To find cost per ounce, we have to divide this by 16.

So,

Cost Per Ounce = \frac{1.5625}{16}=0.097

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5 0
3 years ago
Find the two intersection points
bogdanovich [222]

Answer:

Our two intersection points are:

\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)

Step-by-step explanation:

We want to find where the two graphs given by the equations:

\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1

Intersect.

When they intersect, their <em>x-</em> and <em>y-</em>values are equivalent. So, we can solve one equation for <em>y</em> and substitute it into the other and solve for <em>x</em>.

Since the linear equation is easier to solve, solve it for <em>y: </em>

<em />\displaystyle y = -\frac{3}{4} x + \frac{1}{4}<em />

<em />

Substitute this into the first equation:

\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16

Simplify:

\displaystyle (x+1)^2 + \left(-\frac{3}{4} x  + \frac{9}{4}\right)^2 = 16

Square. We can use the perfect square trinomial pattern:

\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16

Multiply both sides by 16:

(16x^2+32x+16)+(9x^2-54x+81) = 256

Combine like terms:

25x^2+-22x+97=256

Isolate the equation:

\displaystyle 25x^2 - 22x -159=0

We can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 25, <em>b</em> = -22, and <em>c</em> = -159. Substitute:

\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}

Evaluate:

\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}

Hence, our two solutions are:

\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}

We have our two <em>x-</em>coordinates.

To find the <em>y-</em>coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2

And:

\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}

Thus, our two intersection points are:

\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)

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