It sounds like <em>R</em> is the region (in polar coordinates)
<em>R</em> = {(<em>r</em>, <em>θ</em>) : 2 ≤ <em>r</em> ≤ 3 and 0 ≤ <em>θ</em> ≤ <em>π</em>/2}
Then the integral is

6m3 - 16m2 + 15m - 40<span> Simplify —————————————————————
2m2 + 5
</span>Checking for a perfect cube :
<span> 4.1 </span> <span> 6m3 - 16m2 + 15m - 40</span> is not a perfect cube
Trying to factor by pulling out :
<span> 4.2 </span> Factoring: <span> 6m3 - 16m2 + 15m - 40</span>
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 15m - 40
Group 2: <span> -16m2 + 6m3</span>
Pull out from each group separately :
Group 1: (3m - 8) • (5)
Group 2: <span> (3m - 8) • (2m2)</span>
-------------------
Add up the two groups :
<span> (3m - 8) • </span><span> (2m2 + 5)</span>
<span>Which is the desired factorization</span>
<span>3m-8 is the answer</span>
Answer:
x = 6 or x = -7
Step-by-step explanation:
Solve for x over the real numbers:
x^2 + x - 42 = 0
The left hand side factors into a product with two terms:
(x - 6) (x + 7) = 0
Split into two equations:
x - 6 = 0 or x + 7 = 0
Add 6 to both sides:
x = 6 or x + 7 = 0
Subtract 7 from both sides:
Answer: x = 6 or x = -7
Answer: 20 cm
To solve this, use the Pythagorean Theorem, a² + b² = c², where a and b are the legs of the right triangle, and c is the hypotenuse of the right triangle.
**The Pythagorean Theorem only works for right triangles.**
Substitute in the values.
a² + b² = c²
12² + 16² = c²
Solve for c, the hypotenuse.
12² + 16² = c²
144 + 256 = c²
400 = c²
c = √400
c = 20