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3 years ago

Round to the nearest whole number 2.09

Mathematics

1 answer:

Wewaii [24]3 years ago

6 0

Answer:

the answer is 2

Step-by-step explanation:

this is because when you round 2.09 to the nearest whole number it is 2

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50 ÷ (-5) = Please simplify

mafiozo [28]

Answer:

-10

Step-by-step explanation:

50 ÷ (-5)

First ignore the brackets and the negative sign.

Then divide 50 by 5 to get 10

Then return the negative sign so the answer is; -10

3 0

3 years ago

3/5 is the same as 3.5 Is he correct?

Alexxx [7]

He is not correct because 3.5 is actually 3 and 1/2
not 3/5
hope that helps @:)

5 0

3 years ago

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Prove that {(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago

In the problem 4x + 10 list a term, factor, coefficient, and constant.

kifflom [539]

term- 4x and 10

This is because to be a term it has to be + or -

Factor- 4x+10

This is because that is what is happening in the problem

Coefficient- 4y

I don't know what the constant would be, But I hope that this helps you

6 0

3 years ago

-233.2 - 25.8 Please help.

Anon25 [30]

Answer:

-259

Step-by-step explanation:

brainliest

3 0

2 years ago

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Round to the nearest whole number 2.09​

Round to the nearest whole number 2.09