1/4 times X -1+ 3X equals 2

Shirley graphed the line shown on the coordinate plane

Rus_ich [418]

But this is not a question. proof? no question mark

8 0

2 years ago

Log(4)+log(2)-log(5)

Otrada [13]

   log(4) + log(2) - log(5)

   = log(2²) + log(2) - log(5)

   = 2 log(2) + log(2) - log(5)

   = 3 log(2) - log(5)

   = log(2³) - log(5)

   = log (2³/5)

   = log (8/5)

   = log (1.6) = 0.2041... (rounded)

5 0

3 years ago

Read 2 more answers

List the ages of your family and find the average age 55,34,26,24,19,17

Dmitriy789 [7]

Answer:

Soln: 

 

 Total ages = 175

 No. of ages= 6 

 Now,

Average age= Total ages/no. of ages

 

 = 175/6 

 = 29.167 ans.

4 0

2 years ago

3x + 4y = 14 x = 2y - 12 Which point satisfies both equations?

kicyunya [14]

The answer is x and 14

5 0

3 years ago

Read 2 more answers

The marketing club at school is opening a student store. They randomly survey 50 students about how much money they spend on lun

Luden [163]

Answer:

The expected value for a student to spend on lunch each day = $5.18

Step-by-step explanation:

Given the data:

Number of students______$ spent

2 students______________$10

1 student________________$8

12 students______________$6

23 students______________$5

8 students_______________$4

4 students_______________$3

Sample size, n = 50.

Let's first find the value on each amount spent with the formula:

$\frac{num. of students}{sample size} * dollar spent$

Therefore,

For $10:

$\frac{2}{50} * 10 = 0.4$

For $8:

$\frac{1}{50} * 8 = 0.16$ l

For $6:

$\frac{12}{50} * 6 = 1.44$

For $5:

$\frac{23}{50} * 5 = 2.3$

For $4:

$\frac{8}{50} * 4 = 0.64$

For $3:

$\frac{4}{50} * 3 = 0.24$

To find the expected value a student spends on lunch each day, let's add all the values together.

Expected value =

$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24

= $5.18

Therefore, the expected value for a student to spend on lunch each day is $5.18

7 0

2 years ago