Question

How many cubic blocks with a side length of 3/8 cm will be required

Answer 1

ANSWER

The correct answer is A.

EXPLANATION

The volume of a cube is given by

$V=l^3$

First we find the volume of the cube with side length $\frac{3}{4}cm$

$V_{Cube}=(\frac{3}{4})^3$

$V_{Cube}=\frac{27}{64} cm^3$

Next, we find the volume of the cubic block with side length $\frac{3}{8}cm$

$V_{Block}=(\frac{3}{8})^3$

$V_{Block}=\frac{27}{512} cm^3$

We divide the volume of the cube by the volume of the block to get the number of cubic blocks

$Number\: of \: blocks=\frac{\frac{27}{64}} {\frac{27}{512}}$

$Number\: of \: blocks=\frac{27}{64} \times \frac{512}{27}$

$Number\: of \: blocks=\frac{1}{1} \times \frac{8}{1}=8$

Answer 2

Answer:

The correct answer is option A.

8 blocks are needed to fill the box.

Step-by-step explanation:

Given data:

Side length of a block = 3/8 cm

Side length of main block = 3/4 cm

How many blocks are needed to fit in main blocks = ?

Solution:

Volume  = length³

Volume of one simple block = (3/8)³ = 27/512 cm³

Volume of one Main block = (3/4)³ = 27/64 cm³

Blocks are needed to fit in main blocks = (27/64) ÷ (27/512) = 8

                                                            Answer = 8 blocks

Hence 8 simple small blocks of one side length 3/8 cm will needed to fit in the main block of side length 3/4 cm.