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irina1246 [14]
4 years ago
15

How many cubic blocks with a side length of 3/8 cm will be required

Mathematics
2 answers:
alexandr1967 [171]4 years ago
4 0

ANSWER


The correct answer is A.


<u>EXPLANATION</u>


The volume of a cube is given by

V=l^3

First we find the volume of the cube with side length \frac{3}{4}cm

V_{Cube}=(\frac{3}{4})^3


V_{Cube}=\frac{27}{64} cm^3


Next, we find the volume of the cubic block with side length \frac{3}{8}cm

V_{Block}=(\frac{3}{8})^3


V_{Block}=\frac{27}{512} cm^3


We divide the volume of the cube by the volume of the block to get the number of cubic blocks

Number\: of \: blocks=\frac{\frac{27}{64}} {\frac{27}{512}}


Number\: of \: blocks=\frac{27}{64} \times \frac{512}{27}


Number\: of \: blocks=\frac{1}{1} \times \frac{8}{1}=8


Butoxors [25]4 years ago
4 0

Answer:

<u>The correct answer is option A.</u>

<u>8 blocks are needed to fill the box.</u>

Step-by-step explanation:

Given data:

Side length of a block = 3/8 cm

Side length of main block = 3/4 cm

How many blocks are needed to fit in main blocks = ?

Solution:

Volume  = length³

Volume of one simple block = (3/8)³ = 27/512 cm³

Volume of one Main block = (3/4)³ = 27/64 cm³

Blocks are needed to fit in main blocks = (27/64) ÷ (27/512) = 8

                                                            Answer = 8 blocks

Hence 8 simple small blocks of one side length 3/8 cm will needed to fit in the main block of side length 3/4 cm.


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