Find tenth term of the sequence (1,1,2,3,5,8,13)
1 answer:
This is what we call a Fibonacci sequence:
Notice that after the 1,1:
4th term =3 ==> 2+1
5th term =5 ==>3+2
6th term =8==> 5+3
7th term = 13==> 8+5
8th term =...........13+8 =21
9th term = ...........21+13 =34
10t=h term =........34+21 = 55
In short each number equal the sum of the 2 preceding number
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