All categories

3 years ago

Unit Rate Comparison Practice

Mathematics

1 answer:

Rama09 [41]3 years ago

5 0

Answer:

$\frac{2}{41} \: of \: a \: cup \: of \: sugar \: on \: 4 \: cups \: of \: a \: flour$

Step-by-step explanation:

$3:246=x:4 \\ \frac{3}{246} = \frac{x}{4} \: \: = > \: \: x = \frac{3 \times 4}{246} = \frac{12}{246} = \frac{2}{41}$

You might be interested in

Cristobal is comparing the membership club fees at two different bookstores. At the first bookstore, it costs $17.05 annually to

Kruka [31]

Answer:

A) Cristobal need to spend $115.2 in a year for the membership at the second bookstore to be the better value.

Step-by-step explanation:

Let x : Amount Cristobal needs to spend for 2nd membership to be better.

At First bookstore:

Member ship fee = $17.05

The savings on purchase = 15%

So, actual payment = x - (15% of x)

= x - 0.15 x = 0.85 x

So, the total payment in first bookstore

= Membership fee + Purchase payment

= $17.05 + 0.85 x

or, the amount paid at first book store = $17.05 + 0.85 x

At Second bookstore:

Member ship fee = $28.57

The savings on purchase = 25%

So, actual payment = x - (25% of x) = x - 0.125 x = 0.75 x

So, the total payment in first bookstore = $28.57+ 0.75 x

Now, payment made at second store >Payment at first store

⇒$28.57+ 0.75 x > $17.05 + 0.85 x

or, 18-57 - 17-05 > 0.85 x - 0.75 x

or, 0.10x < 11.52

or, x < 11.52/0.10 = 115.2

or, x < 115.2

Hence, Cristobal need to spend $115.2 in a year for the membership at the second bookstore to be the better value.

7 0

3 years ago

Write the ratio of 4 teachers to 134 students in simplest form.?

Nuetrik [128]

It would be 4/134, and simplified that is 2/67.

So it would be 2 teachers to 67 students

5 0

3 years ago

Read 2 more answers

Lyle and Tom are each buying houses just outside of Austin. Lyle has excellent credit,

suter [353]

Answer:

103.96

Step-by-step explanation:

The answer is 939.44 - 835. 48

we can do like: 939.44 - 835. 48 = 103.96 ( 938 -835 = 103 and 144 - 48 = 96).

Have a good day

6 0

3 years ago

A sample of 200 college freshmen was asked how many hours per week they spent playing video games. The following frequency distr

JulsSmile [24]

Answer:

$\% Below\ 50 = 88 \%$

$\% 43\ or\ more = 17 \%$

Step-by-step explanation:

Given

$Total = 200$

<em>The attachment presents the table properly</em>

Solving (a): Percentage of those who play for less than 50 hours weekly

To do this, we simply consider the frequency of students that fall within:

1.0 - 7.9, 8.0 - 14.9,......,43.0 - 49.9

Their frequency is:

$Frequency = 21 + 37 + 40 + 27 + 23 + 18 + 10$

$Frequency = 176$

The percentage is then calculated as:

$\% Below\ 50 = \frac{Frequency}{Total} * 100\%$

$\% Below\ 50 = \frac{176}{200} * 100\%$

$\% Below\ 50 = \frac{176* 100}{200} \%$

$\% Below\ 50 = \frac{176* 1}{2} \%$

$\% Below\ 50 = \frac{176}{2} \%$

$\% Below\ 50 = 88 \%$

Solving (b): Percentage of those who play for 43 or more hours weekly

To do this, we simply consider the frequency of students that fall within:

43.0 - 49.9,......,64.0 - 70.9

Their frequency is:

$Frequency = 10 + 7 + 5+12$

$Frequency = 34$

The percentage is then calculated as:

$\% 43\ or\ more = \frac{Frequency}{Total} * 100\%$

$\% 43\ or\ more = \frac{34}{200} * 100\%$

$\% 43\ or\ more = \frac{34* 100}{200} \%$

$\% 43\ or\ more = \frac{34* 1}{2} \%$

$\% 43\ or\ more = \frac{34}{2} \%$

$\% 43\ or\ more = 17 \%$

7 0

3 years ago

Please help fast<3 Select all the correct answers.

Nookie1986 [14]

Answer:

5 times 8

4 times 10

and im pretty sure that it

Step-by-step explanation:

8 0

3 years ago