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jeyben [28]
3 years ago
11

Problem

Mathematics
1 answer:
Contact [7]3 years ago
8 0

Answer:

<em>The width of the lid is 15 cm</em>

Step-by-step explanation:

<u>The Perimeter of a Rectangle</u>

Given a rectangle of width W and height H, the perimeter is calculated as:

P = 2(W + L)

Jon used 56 cm of ribbon to go around the edge of a rectangular lid. This means the perimeter is:

2(W + L) = 56

Dividing by 2:

W + L = 28

Since the lid was L=13 cm long, the width is:

W = 28 - 13 = 15

The width of the lid is 15 cm

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Help pls my math teacher is rude​
Digiron [165]

Answer:

2.25 or 2 1/4 pounds

Step-by-step explanation:

if you add them all up (I converted them to decimals when adding) you get 13.5 or 13 1/2 if your using fractions, then you divide that by 6 because thats how many jars there are and you get 2.25 or 2 1/4

5 0
3 years ago
if tom spins the spinner 80 times work out an estimate for the number of times the spinner will land on 3 please help me
NNADVOKAT [17]

Answer:

The estimated number of times the spinner will land on 3 is 20.

Step-by-step explanation:

The complete question is:

A four-sided spinner is provided. If Tom spins the spinner 80 times then work out an estimate for the number of times the spinner will land on 3.

Solution:

Assume that the four-sided spinner is unbiased.

That is all the four outcomes are equally likely to be selected.

The probability that the spinner lands on any of the four numbers is:

P(1) = P (2) = P (3) = P (4) = 0.25

It is provided that Tom spins the spinner <em>n</em> = 80 times.

The spinner can land on any of the four numbers independently.

The random variable <em>X</em>, defined as the number of times the spinner lands on 3, follows a Binomial distribution with parameters <em>n</em> = 80 and <em>p</em> = 0.25.

The expected value of <em>X</em> is:

E(X)=np

        =80\times 0.25\\=20

Thus, the estimated number of times the spinner will land on 3 is 20.

7 0
2 years ago
if an external point of a circle is at a distance equal to the diameter of the circle from the center of the circle, the length
jeka57 [31]

Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem

t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).

So t = √(3r^2) = √3r answer.

7 0
3 years ago
Wiil mark bianleast plz plz hlpe
Andrews [41]

Answer:

18 since 12 x 2 = 24 so 9 x 2 = 18

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If ABCD is an A4 sheet and BCPO is the square, prove that △OCD is an isosceles triangle. And find the angles marked as 1 to 8 wi
Dmitry [639]

Answer:

The diagram for the question is missing, but I found an appropriate diagram fo the question:

Proof:

since OC = CD = 297mm Therefore, Δ OCD is an isoscless triangle

∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

∠DOP = 22.5°

∠PDO = 67.5°

∠ADO = 22.5°

∠AOD = 67.5°

Step-by-step explanation:

Given:

AB = CD = 297 mm

AD = BC = 210 mm

BCPO is a square

∴ BC = OP = CP = OB = 210mm

Solving for OC

OCB is a right anlgled triangle

using Pythagoras theorem

(Hypotenuse)² = Sum of square of the other two sides

(OC)² = (OB)² + (BC)²

(OC)² = 210² + 210²

(OC)² = 44100 + 44100

OC = √(88200

OC = 296.98 = 297

OC = 297mm

An isosceless tringle is a triangle that has two equal sides

Therefore for △OCD

CD = OC = 297mm; Hence, △OCD is an isosceless triangle.

The marked angles are not given in the diagram, but I am assuming it is all the angles other than the 90° angles

Since BC = OB = 210mm

∠BCO = ∠BOC

since sum of angles in a triangle = 180°

∠BCO + ∠BOC + 90 = 180

(∠BCO + ∠BOC) = 180 - 90

(∠BCO + ∠BOC) = 90°

since ∠BCO = ∠BOC

∴  ∠BCO = ∠BOC = 90/2 = 45

∴ ∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

For ΔOPD

Tan\ \theta = \frac{opposite}{adjacent}\\ Tan\ (\angle DOP) = \frac{87}{210} \\(\angle DOP) = Tan^-1(0.414)\\(\angle DOP) = 22.5 ^{\circ}

Note that DP = 297 - 210 = 87mm

∠PDO + ∠DOP + 90 = 180

∠PDO + 22.5 + 90 = 180

∠PDO = 180 - 90 - 22.5

∠PDO = 67.5°

∠ADO = 22.5° (alternate to ∠DOP)

∠AOD = 67.5° (Alternate to ∠PDO)

3 0
3 years ago
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