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sergiy2304 [10]
4 years ago
8

50

Mathematics
1 answer:
Lera25 [3.4K]4 years ago
7 0

Answer:

I think the answer would be 10.

Correct me if im wrong tho please.

Step-by-step explanation:

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Simplify (3a^3 b^3)(4ab^2)^2
mamaluj [8]
\bf (3a^3b^3)(4ab^2)^2\implies (3a^3b^3)(4^2a^2b^{2\cdot 2})\implies (3a^3b^3)(4^2a^2b^4)
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3a^3b^34^2a^2b^4\implies 3\cdot 4^2a^3a^2b^3b^4\implies 3\cdot  16a^{3+2}b^{3+4}\implies 48a^5b^7
7 0
3 years ago
N a number line, the directed line segment from Q to S has endpoints Q at –8 and S at 12. Point R partitions the directed line s
Evgen [1.6K]
Answer: Point R will be at the number 8 on the number line.

From -8 to 12, there are 20 numbers. If we want to get a ratio of 4:1, we need to have 5 equal sections.

20 / 5 = 4

Since the ratio is 4:1 to R, we need to move 4 x 4 = 16 spaces from -8.

-8 + 16 = 8

Look for the equation that gives you a value of 8.
5 0
3 years ago
Read 2 more answers
Exactly one of the die is a four
Ksju [112]
Care to explain more ??
5 0
3 years ago
When studying radioactive​ material, a nuclear engineer found that over 365​ days, 1,000,000 radioactive atoms decayed to 973 co
scoray [572]

Answer: A) 71.498 ; b) 0.00152

Step-by-step explanation:

Given the following :

Number of atoms that decayed during 365 days period = 26,097

Number of days = 365

Mean number of radioactive atoms that decayed in a day:

Mean = number of decayed atoms / number rof days

Mean = 26,097 / 365

Mean = 71.498 atoms per day

B.) probability that 50 radioactive atoms decayed in a given day:

Using the poisson distribution formula :

P(x =x) = (m^x * e^-m) ÷ x!

Where m = mean

Mean (m) = 71.498

P(x = 50) = (71.498^50 * e^-71.498) / 50!

P(x = 50) = (71.498^50 * 2.7182818^-71.498) / 50!

= 4.60795E61 / 50!

= 0.0015150

6 0
3 years ago
Given the median line QR and trapezoid MNOP, what is the value of x? MN=17 QR=x+12 OP=5x-14
kari74 [83]
<u><em>Answer:</em></u>
x = 7
MN (first base) = 17 units
OP (second base) = 21 units
QR (median) = 19 units

<u><em>Explanation:</em></u>
In a trapezium, the length of the median is equal to half the sum of the two bases.

<u>From the given, we have:</u>
MN (first base) = 17 units
OP (second base) = 5x - 14 units
QR (median) = x + 12 units

<u>Applying the above rule:</u>
median = 0.5 (first base + second base)
x + 12 = 0.5 (17+5x-14)
2(x+12) = 17+5x-14
2x + 24 = 3 + 5x
24-3 = 5x-2x
21 = 3x
x = \frac{21}{3}
x = 7

<u>Based on the above, the lengths would be:</u>
MN (first base) = 17 units
OP (second base) = 5x - 14 = 5(7) - 14 = 21 units
QR (median) = x + 12 = 7 + 12 = 19 units

Hope this helps :)
7 0
3 years ago
Read 2 more answers
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