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2 years ago

What is the value of c?

Mathematics

1 answer:

Luden [163]2 years ago

5 0

Answer:

Step-by-step explanation:

Explanation:

Since it is a right triangle and we are given the two shorter legs, the hypotenuse is found by

100

576

676

√

676

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$925 at 2% interest for 2.4 years. Find the simple interest earned.

mixer [17]

Answer:

£43

Step-by-step explanation:

925×2/100

=£ 18.5

2.4 years =18.5×2.4

=£43

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3 years ago

Is parallelogram a rectangle

denis-greek [22]

Answer:

Sometimes, but not always.

Step-by-step explanation:

A parallelogram is a quadrilateral with two pairs of parallel sides, but there are no requirements for its interior angles. A rectangle, on the other hand, <em>must</em> have four interior 90 degree angles. So a rectangle is always a parallelogram, but a parallelogram is not always a rectangle.

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3 years ago

Read 2 more answers

Find all values of the angle θ (in radians, with 0 ≤ θ < 2π) for which the matrix a = cos θ −sin θ sin θ cos θ has real eigen

harina [27]

The matrix

$A=\begin{bmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{bmatrix}$

has eigenvalues $\lambda$ such that

$\det(A-\lambda I)=\begin{vmatrix}\cos\theta-\lambda&-\sin\theta\\\sin\theta&\cos\theta-\lambda\end{vmatrix}=0$

$(\cos\theta-\lambda)^2+\sin^2\theta=0$

$(\cos\theta-\lambda)^2=-\sin^2\theta$

$\cos\theta-\lambda=\pm\sqrt{-\sin^2\theta}$

$\lambda=\cos\theta\pm\sqrt{-\sin^2\theta}$

$\sin^2\theta\ge0$ for all values of $\theta$ , so we need to have $\sin\theta=0$ in order for $\lambda$ to be real-valued. This happens for

$\sin\theta=0\implies\theta=n\pi$

where $n$ is any integer, and over the given interval we have $\theta=0$ and $\theta=\pi$ .

4 0

3 years ago

Oscar's Burger Place made 11 burgers with onions and 38 burgers without onions. What is

Vika [28.1K]

Answer:

11 : 38

Step-by-step explanation:

7 0

2 years ago

given that the center of a circle is at point (-3,5) and that the radius of the circle is 6 units, write the the equation of the

Anika [276]

The equation of a cricle is
$(x-h)^{2}+(y-k)^{2}=r^{2}$
h being the x coordinate of the given point and k being the y coordinate of the given point (r also being the radius).

Now we have to plug the points into the equation
$(x--3)^{2} +(y-5)^{2} = 6^{2}$
now just simplify the the equation
$(x+3)^{2} +(y-5)^{2} = 36$

3 0

3 years ago