Answer:
88.51 is the minimum score needed to receive a grade of A.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 73
Standard Deviation, σ = 11
We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.
Formula:
![z_{score} = \displaystyle\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z_%7Bscore%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
We have to find the value of x such that the probability is 0.0793.
Calculation the value from standard normal z table, we have,
![P(z \leq 1.410) = 0.9207](https://tex.z-dn.net/?f=P%28z%20%5Cleq%201.410%29%20%3D%200.9207)
Hence, 88.51 is the minimum score needed to receive a grade of A.
If i were going by guesses i’d say y=x. sorry if i’m wrong.
Answer:
165 Students Have No Made Plans For Lunch.
Step-by-step explanation:
According To the Question,
- Given,On a school trip to a theme park, 4 busses each carry 70 students Then Total Number Of Students on a trip is 70×4=280 Students.
- And,35% of the students are bringing their own lunch. Thus,35% Of 280 Students is 98 Students. Then Remaining 182 Students not bring their own lunch.
Now, 17 of the students are buying lunch when they get to the theme park. Thus students Who have not made plans for lunch is 182-17⇒165Students
Answer:
$138,345
Step-by-step explanation:
This is a compound decline problem, which will be solve by the compound formula:
![F=P(1-r)^t](https://tex.z-dn.net/?f=F%3DP%281-r%29%5Et)
Where
F is the future value (value of house at 2030, 14 years from 2016)
P is the present value ($245,000)
r is the rate of decline, in decimal (r = 4% = 4/100 = 0.04)
t is the time in years (2016 to 2030 is 14 years, so t = 14)
We substitute the known values and find F:
![F=P(1-r)^t\\F=245,000(1-0.04)^{14}\\F=245,000(0.96)^{14}F=138,344.96](https://tex.z-dn.net/?f=F%3DP%281-r%29%5Et%5C%5CF%3D245%2C000%281-0.04%29%5E%7B14%7D%5C%5CF%3D245%2C000%280.96%29%5E%7B14%7DF%3D138%2C344.96)
Rounding it up, it will be worth around $138,345 at 2030