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2 years ago

What is a collinear point?

Mathematics

2 answers:

Viefleur [7K]2 years ago

5 0

Three or more points on a straight line

vlabodo [156]2 years ago

4 0

3 or more points lying on a single straight line

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In a certain country, the car number plate is formed by 4 digits from the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 followed by 2 l

elena-s [515]

Answer:

none, because without the letters and numbers.the plate number can not be identify or formed

3 0

1 year ago

7) 6x + 16 + = 2x + 28

Ede4ka [16]

Answer: the answer to number seven is x=3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

12. What is the equation of a circle with center (-7, -3) and radius 2?

Genrish500 [490]

Answer:

(x + 7)^2 + (y + 3)^2 = 4

Step-by-step explanation:

The standard equation of a circle is:

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the center and r is the radius. We can substitute the information given to obtain:

(x + 7)^2 + (y + 3)^2 = 4

3 0

2 years ago

Find the equation of the tangent line to the curve 2exy=x+y at (0,2).

DiKsa [7]

Answer:

The equation of the tangent line to the curve

3 x - y = 2

Step-by-step explanation:

Step(i):-

Given function = f(x,y) = $2e^{xy} -x-y=0$ ...(i)

Differentiating equation (i) with respective to 'x' , we get

$2 e^{xy} \frac{d}{d x} (x y) -1 -\frac{dy}{dx} =0$

apply formula

$\frac{d}{dx} (UV) = UV^{l} +V U^{l}$

step(ii):-

⇒ $2 e^{xy} (x(\frac{d}{d x} ( y))+y(1)) -1 -\frac{dy}{dx} =0$

⇒ $2 e^{xy} (x(\frac{d}{d x} ( y))+ 2e^{xy} y(1)) -1 -\frac{dy}{dx} =0$

Taking common d y/d x

$(2 e^{xy} (x) -1)\frac{dy}{dx} =1- 2e^{x y} y(1))$

$\frac{dy}{dx} =\frac{1- 2e^{x y} y(1))}{(2 e^{xy} (x) -1)}$

put At (0,2)

$\frac{dy}{dx} =\frac{1- 2e^{0} 2(1))}{(2 e^{0} (0) -1)}=\frac{1-4}{-1} =3$

slope of the curve m = 3

Step(iii):-

The equation of the tangent line to the curve

$y-y_{1} =m(x-x_{1} )$

y - 2 = 3 ( x - 0 )

3 x - y = 2

Final answer:-

The equation of the tangent line to the curve

3 x - y = 2

8 0

2 years ago

Me need big brain to answer this question c:

Ganezh [65]

Answer:

$y=\dfrac{3}{2}x\ ...(i)\\\\ z=\dfrac{5}{2}x\ ...(ii)\\\\ z=x+y\ ....(iii)$

Step-by-step explanation:

Let x be the amount of dough required for small pizza, y be the amount of dough required for medium pizza and z be the amount of dough required for large pizza.

As per the question , we have

$y=\dfrac{3}{2}x\ ...(i)\\\\ z=\dfrac{5}{2}x\ ...(ii)\\\\ z=x+y\ ....(iii)$

Hence, the equation for the question with the variable representing the amount of dough needed for small pizza.

$y=\dfrac{3}{2}x\ ...(i)\\\\ z=\dfrac{5}{2}x\ ...(ii)\\\\ z=x+y\ ....(iii)$

3 0

2 years ago