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miv72 [106K]
3 years ago
7

Gigi needs 243 straws for an art project. If straws are sold in packages of 25, about how many packages will Gigi need?

Mathematics
2 answers:
Aleks04 [339]3 years ago
7 0

Answer:

9.72

Step-by-step explanation:

i dhdjskndjeksndvjdnsbdhdjsndbdhdjdjdjdbrbjsjdbd

solniwko [45]3 years ago
5 0
Since a packages contain 25. And Gigi needs 243straws.To get the numbers of packages you divide the number of straw needed by the number in a package.that is 243/25=9.72.Aproximate 10 packages
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Simplified the answer is in decimal form 0.00000026.
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finlep [7]

3√5

The distance between two points on an XY plane is calculated using the distance formula, which is employed in coordinate geometry or Euclidean geometry. The x-coordinate, often known as the abscissa, is a point's separation from the y-axis. The y-coordinate, often known as the ordinate, refers to a point's separation from the x-axis. A point on the x-axis has coordinates of the form (x, 0), and a point on the y-axis has coordinates of the form (0, y). We utilize the Pythagoras theorem in this case to determine the separation between any two points in a plane.

Distance formula = √ ( x₁ - x₂)² + ( y₁ - y₂)²

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To learn more about distance formula, refer to brainly.com/question/7243416

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2 years ago
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Step-by-step explanation:

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3 years ago
Which type of angle is ABC
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Your state is considering raising the legal age for consumption of alcoholic beverages to 21 years old. How large a sample size
julsineya [31]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.01}{2.58})^2}=16641  

And rounded up we have that n=16641

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

For this case we can use as estimator for the proportion \hat p =0.5, since we don't have any other previous info. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.01}{2.58})^2}=16641  

And rounded up we have that n=16641

8 0
3 years ago
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