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Romashka [77]
3 years ago
6

A number has eight factors

Mathematics
2 answers:
konstantin123 [22]3 years ago
5 0
Number they all go in is 30 . So the other 3 factors of 30 are 15, 6 and 30

serious [3.7K]3 years ago
3 0
Im not sure but 4,6,7,8,9
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(f/g)(x)and (f/g)(7)
Phoenix [80]

Answer:

(\frac{f}{g})(x)=\frac{f(x)}{g(x)}\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}

Step-by-step explanation:

Division operation of function:If\ f(x)\ and\ g(x)\ are\ two\ functions\ then\ (\frac{f}{g})(x)=\frac{f(x)}{g(x)}

Here\ we\ have\ to\ find\ (\frac{f}{g})(7)\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}

Example:

Take\ f(x)=3x^2+1,\ g(x)=x+1\\\\(\frac{f}{g})(x)=\frac{f(x)}{g(x)}\\\\(\frac{f}{g})(x)=\frac{3x^2+1}{x+1}\\\\f(7)=3\times 7^2+1\\\\f(7)=3\times 49+1\\\\f(7)=148\\\\g(7)=7+1\\\\g(7)=8\\\\(\frac{f}{g})(7)=\frac{f(7)}{g(7)}\\\\(\frac{f}{g})(x)=\frac{148}{8}

7 0
3 years ago
In the equation 8x - 1=3x+4 the variable x represents the same value. Which value of x is the solution of the equation x = 0 1 2
OleMash [197]

the AnSwEr is

12 because 8x - 1=3x+4 the variable x represents the same value and x= 0

7 0
3 years ago
Emma pays 10$ to join a gym. For the first 5 months she pays a monthly 15$ membership fee. For problems 6-7 use the explicit rul
Ne4ueva [31]

Answer: For the first 5 months she pays a monthly$15 membership fee. Use the explicit rule f(n) = 15n + 10

Step-by-step explanation:

3 0
3 years ago
Christopher just found beautiful yarn for 20% off at his favorite yarn store. He can make one scarf from 2/3 of a ball of yarn.
bija089 [108]
Christopher would be able to make 18 scarves.

To solve this problem, we just need to divide 12 by 2/3. To divide 12 by 2/3, we just multiply 12 by 3/2.

This will give us 36 over 2 or just 18.
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=4%20%5Ctimes%208%20%5E%7B2x%20%2B%201%3F%7D%20%20%3D%2032%20%5E%7Bx%20%2B%202%7D%20" id="TexFo
svet-max [94.6K]

Answer:

x = 5

Step-by-step explanation:

<u>__________________________________________________________</u>

<u>FACTS TO KNOW BEFORE SOLVING</u> :-

  • a^x \times a^y = a^{x+y}
  • In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. : a^x = a^y  ⇒  x = y  [∵ Bases are equal on both the sides]

<u>__________________________________________________________</u>

4 \times 8^{2x+1} = 32^{x+2}

Lets express it in terms of 2.

=> 2^2 \times 2^{3 (2x+1)} = 2^{5(x+2)}

=> 2^2 \times 2^{6x+3} = 2^{5x+10}

=> 2^{2 + 6x+3} = 2^{5x+10}

=> 2^{6x+5} = 2^{5x+10}

Here the bases on both the sides are equal. Hence ,

=> 6x + 5 = 5x + 10

=> 6x - 5x = 10 - 5

=> x = 5

6 0
3 years ago
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