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snow_tiger [21]
3 years ago
11

Determine whether the points p and q lie on the given surface. r(u, v) = u + v, u2 − v, u + v2 p(3, 3, 3), q(4, −2, 10)

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0

Answer:

If  p  and q  lie on the surface , then we should be able to find values of  u  and  v  such that they can satisfy the equation of the surface.

i.e

x = u+v;  

y = u^2 - v and

z = u + v^2

For p we have to find u and v such that:

u + v =3 ;                      ......[1]

u^2 - v = 3 ;     .....[2]

u + v^2 = 3       .....[3]

Equate [1] and [3] we have;

u + v = u + v^2

Subtract u from both sides we get;

u + v -u= u + v^2-u

Simplify:

v = v^2

or

v^2 - v = v(v-1) = 0

⇒ v = 0 and v = 1

To find the value of u substitute the values of v in [1]

for v =0

u + 0 = 3

u = 3

for v = 1

u + 1 = 3

Subtract 3 from both sides we get;

u =  2

Now; substitute the values of u and v in equation [2] to satisfy:

if u = 3 ad v = 0

then;

u^2 - v = 3

3^2 - 0 = 3

9 = 3 which is not true

if u =2 and v =1

then;

2^2 - 1 = 3

4-1 = 3

3 = 3 which is true.

Therefore, the point p lies on the given surface with u = 2 and v =1

Similarly, for q we have to find u and v such that:

u + v =4 ;                      ......[1]

u^2 - v = -2 ;     .....[2]

u + v^2 = 10       .....[3]

Adding first two equation; we get

u + v +u^2 -v = 4-2

Simplify:

u^2+u -2 =0

or

(u+2)(u-1) = 0

⇒ u = -2 and u = 1

from [1] we have  v = 4- u

For u = -2

then;

v = 4-(-2) = 4+2

v = 6

For u = 1

then;

v = 4-1

v =3

Now; substitute the values of u and v in equation [3] to satisfy:

if u = -2 ad v = 6

then;

u +v^2 = 10

-2 +6^2 = 10

-2 +36 = 10

34 = 10 which is not true

if u = 1 ad v = 3

then;

u +v^2 = 10

1 +3^2 = 10

1 +9 = 10

10 = 10 which is not true.

Therefore, the point q lies on the given surface with u=1 and v =3

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