The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
Read more about exponential functions at:
brainly.com/question/11464095
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Answer:
94
Step-by-step explanation:
94444444444444444444444444
Yes it is equal
75/100=15/20=3/4
The perimeter would be ≈ 36.797836892947.
Rounded would be about 37, or 36.8.
Hope this helps!!!!
Solving for P:
≈36.79784
Hope this helps!!
Answer:
It look right to me
Step-by-step explanation:
