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3 years ago

Factorise 2a – 4a3 + 6abc

Mathematics

1 answer:

Viefleur [7K]3 years ago

7 0

The answer for this will be

2a(1-2a ²+3bc)

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15 added to the product of 13 times 2

snow_tiger [21]

Answer: 41

Step-by-step explanation:

Product would be the answer to a multiplication equation. So the product of 13 times 2 would be 26. Then you add 15 to the product.

So the answer is 41

13x2=26

26+15=41

5 0

3 years ago

Read 2 more answers

What is the remainder when (3x4 + 2x3 – x2 + 2x – 14) ÷ (x + 2) ?

Tpy6a [65]

Answer:

Remainder: 10

Step-by-step explanation:

Given: $(3x^4+2x^3-x^2+2x-14)\div (x+2)$

We need to find the remainder of the division polynomial.

Using synthetic division:

-2 | 3 2 -1 2 -14 |

-6 8 -14 24

3 -4 7 -12 10

Please see the attachment for steps.

At last we get a number 10.

Therefore, 10 is remainder of division.

8 0

3 years ago

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Which number has a repeating decimal form?

nikitadnepr [17]

Answer:

answer d 2/6

which is 1/3 =0.333333333

5 0

3 years ago

Solve <br> f(x)=4x5−8x4+8x2−4x

Goryan [66]

Given:

The function is:

$f(x)=4x^5-8x^4+8x^2-4x$

To find:

The roots of the given equation.

Solution:

We have,

$f(x)=4x^5-8x^4+8x^2-4x$

For roots, $f(x)=0$ .

$4x^5-8x^4+8x^2-4x=0$

$4x(x^4-2x^3+2x-1)=0$

$4x((x^4-1)+(-2x^3+2x))=0$

$4x((x^2+1)(x^2-1)-2x(x^2-1))=0$

On further simplification, we get

$4x(x^2+1-2x)(x^2-1)=0$

$4x(x-1)^2(x+1)(x-1)=0$

$4x(x+1)(x-1)^3=0$

Using zero product property, we get

$4x=0$

$x=0$

Similarly,

$x+1=0$

$x=-1$

And,

$(x-1)^3=0$

$x=1$

Therefore, the zeroes of the given function are $-1,0,1$ and the factor form of the given function is $f(x)=4x(x+1)(x-1)^3$ .

6 0

3 years ago

The answer is C, why does the m2g have to go in the front?

Svetradugi [14.3K]

The answer would be c but why u have d

5 0

4 years ago

Read 2 more answers