The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is 
seconds
So, the time required for 200 wing beat 
seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...
So, the time required for one wing beat is 5 milliseconds.
Answer:
pk oma gawd hey you
Step-by-step explanation:
Your answer is <span>132^2
......</span>
You need to find the total miles he traveled then multiply it by 3.
New York --> Chicago is 714 miles,
Chicago --> Washington is 596 miles,
Washington --> New York is 205 miles.
so total he traveled 1,515 miles.
1,515 x 3 = 4,545.
So D would be your answer (:
Y = 5
3(3y - 15) is also equal to 9y - 45, which means to find y, you have to divide 45 by 9, which is 5.
