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3 years ago

Please help my brain isn’t working

Mathematics

1 answer:

sveta [45]3 years ago

4 0

Answer:

2.25

Step-by-step explanation:

substitute x = -2 into y = (2/3)^x

=> y = (2/3)^-2

=> y = 9/4 = 2.25

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Solve 3x+ 4x = 2. (2 points)<br> O 2t10<br> O-2+2v10<br> 3<br> O-2±10<br> 3<br> O -41v10<br> 3

Norma-Jean [14]

3x+4x=2
You add 3x and 4x which gets you 7x

7x=2
You divide both sides of the equation by 7

x=2/7
This will be your result

3 0

3 years ago

A florist uses 5 red roses for every 2 white

Yakvenalex [24]

Answer is A

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3 years ago

Read 2 more answers

add the term that makes the given expression into a perfect square. write the result as the square of a bracketed expression c s

Molodets [167]

<h2>Perfect Squares</h2>

Perfect square formula/rules:

$a^2+2ab+b^2=(a+b)^2$
$a^2-2ab+b^2=(a-b)^2$

Trinomials are often organized like $ax^2+bx+c$ .

The <em>b</em> value in this case is <em>c</em>, and it will always equal the square of half of the <em>b</em> value.

Perfect square trinomial: $ax^2+bx+(\dfrac{b}{2})^2$
or $ax^2-bx+(\dfrac{b}{2})^2$

<h2>Solving the Question</h2>

We're given:

$c^2-4c$

In a trinomial, we're given the $ax^2$ and $bx$ values. <em>a</em> in this case is 1 and <em>b</em> in this case is 4. To find the third value by dividing 4 by 2 and squaring the quotient:

4 ÷ 2 = 2
2² = 4

Therefore, the term that we can add is + 4.

$c^2-4c+4$

To write this as the square of a bracketed expression, we can follow the rule $a^2-2ab+b^2=(a-b)^2$ :

$(c-2)^2$

<h2>Answer</h2>

$c^2-4c+4$

$(c-2)^2$

4 0

2 years ago

Compute the directional derivative of the function g(x,y)= sin(π(x−5y)).

e-lub [12.9K]

Answer:

Step-by-step explanation:

The directional derivative of a function in a particular direction u is given as the dot product of the unit vector in the direction of u and the gradient of the function

g(x,y) = sin(π(x−5y)

∇g = [(∂/∂x)î + (∂/∂y)j + (∂/∂z)ķ] [sin(π(x−5y))

(∂/∂x) g = (∂/∂x) sin (πx−5πy) = π [cos(π(x−5y))]

(∂/∂y) g = (∂/∂y) sin (πx−5πy) = - 5π [cos (π(x−5y))]

∇g = π [cos(π(x−5y))] î - 5π [cos (π(x−5y))] j

∇g = π [cos (π(x−5y))] [î - 5j]

So, the question requires a direction vector and a point to fully evaluate this directional derivative now.

8 0

3 years ago

My sister can walk from school to home in 35 minutes. I can walk from school to home in 20 minutes. But today I stayed for some

Verizon [17]

Answer: