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serg [7]
3 years ago
9

You are on vacation in Canada. Canada also uses the dollar for currency. The exchange rate is 1 U.S. Dollar is equal to 1.33 Can

adian dollars. You exchange $175 U.S. For Canadian dollars. How many Canadian dollars will you receive?
Mathematics
1 answer:
lidiya [134]3 years ago
3 0

Answer:

You will receive 232.75 CAD

Step-by-step explanation:

This is an exchange rate question.

we proceed as follows;

The exchange rate according to the question is 1 usd to 1.33 cad

What this means is that when you bring 1 usd you’d be getting 1.33 cad

Now you’re bringing 175 usd, the amount of Cad you’ll be getting will be 175 * 1.33 = 232.75 CAD

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25x + 10 = 260<br> Please Help!
madreJ [45]

Answer:

x = 10

Step-by-step explanation:

25x + 10 = 260

=> 25x = 250

=> x = 10

Hoped this helped.

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It is important to know the appropriate dose of ibuprofen for a child so that you are ready in the case of high fever. The dosin
Alexus [3.1K]

Answer:

102 mg

Step-by-step explanation:

Let's convert 28 pounds to kgs.

Since 1 kg = 2.2 pounds, we can find:

\frac{1Kg}{2.2Pounds}=\frac{xKg}{28Pounds}\\1*28=2.2x\\28=2.2x\\x=\frac{28}{2.2}\\x=12.73

So 28 pounds is 12.73 Kg

Since 8mg is given per kg, for 12.73 kg, the amount given should be:

12.73 * 8 = 101.84

Rounded to nearest whole number, that is, 102 mg

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can someone help me, Just the answer don’t worry about explaining everything, Im really bad on Math :(
Strike441 [17]

Answer:

a. -2 b. -2 c. -1 d. 4 e. -3 f. 0

Step-by-step explanation:

The average rate of change formula is:

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}

a.  

We need to find the rate of change for x = -3 to x = -2 so we look on the graph to find y.

At x = -3 it look like y = 0  so

x_{1} = -3

y_{1} = 0

At x = -2 it looks like y = 2

x_{2} = -2

y_{2} = 2

Now we can just plug everything in to the rate of change formula.

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{2- 0}{-3-(-2)} = \frac{2- 0}{-3+2} = \frac{2}{-1} = -2

So for a. our rate of chage for the given interval is -2

b.

Now that you have the formula we don't need to explain each time.

x_{1} = -2

y_{1} = 2

x_{2} = 1

y_{2} = - 4

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-4- 2}{1-(-2)} = \frac{-4-2}{1+2} = \frac{-6}{3} = -2

c.

x_{1} = 0

y_{1} = -3

x_{2} = 1

y_{2} = - 4

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-4-(-3)}{1-0} = \frac{-4 + 3}{1-0} = \frac{-1}{1} = -1

d.

x_{1} = 1

y_{1} = -4

x_{2} = 2

y_{2} = 0

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{0 - (-4)}{2-1} = \frac{0 + 4}{2-1} = \frac{4}{1} = 4

e.

x_{1} = -1

y_{1} = 0

x_{2} = 0

y_{2} = -3

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-3- 0}{0-(-1)} = \frac{-3- 0}{0+1} = \frac{-3}{1} = -3

f.

x_{1} = -1

y_{1} = 0

x_{2} = 2

y_{2} = 0

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{0- 0}{2-(-1)} = \frac{0- 0}{2+1} = \frac{0}{3} = 0

4 0
3 years ago
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