2 years ago

The product of a number t and 6 increased by 1 is equal to 43

Mathematics

1 answer:

Flura [38]2 years ago

5 0

6*7=42 42+1=43 therefore the number you are looking for is 7

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The function is given as:

$\mathbf{h(t) = -16t^2 + 160t}$

Differentiate the function with respect to t

$\mathbf{h'(t) = -32t + 160}$

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So, we have:

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