Either Firewire, or an ethernet cable.
Answer:
- import java.util.Scanner;
- public class Main {
-
- public static void main(String[] args) {
-
- Scanner input = new Scanner(System.in);
- System.out.print("Please enter two characters: ");
- String inputStr = input.nextLine();
-
- if(inputStr.charAt(0) == 'B' || inputStr.charAt(0) == 'b'){
- System.out.println("Biology");
- }
- else if(inputStr.charAt(0) == 'C' || inputStr.charAt(0)== 'c'){
- System.out.println("Computer Science");
- }
- else if(inputStr.charAt(0) == 'I' || inputStr.charAt(0) == 'i')
- {
- System.out.println("Information Technology and Systems");
- }
- else{
- System.out.println("Invalid major");
- }
-
- int num = Character.getNumericValue(inputStr.charAt(1));
-
- if(num >= 1 && num <= 4){
- switch (num){
- case 1:
- System.out.println("freshman");
- break;
- case 2:
- System.out.println("sophomore");
- break;
- case 3:
- System.out.println("junior");
- break;
- case 4:
- System.out.println("senior");
- break;
- }
-
- }
- else{
- System.out.println("Invalid year status");
- }
-
- }
-
- }
Explanation:
The code consists of two main parts. The part 1 is to validate the input major and print out the major according to the input character (Line 10 -22). If the input character is not matched with the target letters, a message invalid major will be displayed.
The part 2 is to validate the year status to make sure it only fall within the range of 1-4 (Line 26 -45). If within the range, the program will display the year major accordingly. If not a message invalid year status will be displayed.
<span>ASP.NET is an open-source server-side web application framework designed for web development to produce dynamic web pages.
Without it, we would be lost on the internet, or possibly wouldn't even have internet. Whats the point of Wifi without web pages?</span>
The name of the user defined function is: footballMatch
Answer:
a) the average CPI for machine M1 = 1.6
the average CPI for machine M2 = 2.5
b) M1 implementation is faster.
c) the clock cycles required for both processors.52.6*10^6.
Explanation:
(a)
The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4
= 1.6
The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4
= 2.5
(b)
The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6
Given 80MHz = 80 * 10^6
The average MIPS ratings for M1 = 80 x 10^6 / 1.6 x 10^6
= 50
Given 100MHz = 100 * 10^6
The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6
= 40
c)
Machine M2 has a smaller MIPS rating
Changing instruction set A from 2 to 1
The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)
and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.
